
<u>Given expression is </u>

can be rewritten as

We know,

And

So, using this identity, we


can be further rewritten as





<u>Hence, </u>

1st box: 2a (subtract 2a from both sides)
2nd box: 3 (add 3 to both sides)
3rd box: 10 (add 7+3)
4th and 5th box: 2 (divide both by 2)
6th box: 5 (10/2=5)
Answer:
-40
Step-by-step explanation:
(-40) divided by 5 is (-8)
so basically what i was thinking of was they sold them in the spring
A:40%
If you put 60 over 150 and x(percent of students) over 100 and cross multiply 100 and 60, you will get 6000. You then divide that by 150 which leaves you with 40 as x and 40 over 100 is 40%.