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I am Lyosha [343]
3 years ago
14

Consider the following equations: −x − y = 1

Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0
Solve for X and y using both equations the point you get will be the point they cross eachother
-x-y=1
y=x+3
-x-(x+3)=1
-x-x-3=1
-2x-3=1
+3 both sides
-2x=4
÷-2 both sides
x=-2
solve for y
y=-2+3
y=1
(-2,1)
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Mathematics please help...​
galben [10]

Answer:

the answer is B

Step-by-step explanation:

area of the minor arc is teter all over 360 times 2 pie r square.

that is

\frac{?}{360}  \times 2\pi {r}^{2}

= but because the question said for length AB, youvhave to use only one radius.

\frac{160}{360}  \times 2 \times  \pi \times 9

You the use 40 to cancel 160 and 360 to get 4 all over 9 times 2 pie times 9.

\frac{4}{9}  \times 2 \times \pi \times 9

You then cancel 9 with 9 to get 4 times 2 times pie

4 \times 2 \times \pi

this is equal to

8\pi

3 0
3 years ago
Explain how the segment addition postulate can be modeled using a real world object
Kazeer [188]
You could model a strait road by using a segment addition postulate. For instance, if you are between point A and B you could calculate how much future you need to go by subtracting the length of the road by the distance you have traveled. Also, segment addition postulate can be used with City Water Lines or Sewer Lines. They can be used to calculate how much pipe is damaged and needs to be replaced.
6 0
3 years ago
A cube with sides numbered 1 to 6 is rolled 300 times. What is the best prediction for the number of times that a 1 or 2 would b
Leno4ka [110]
The answer is A.

Divide 300 by the number of faces of a cube.

Since there are 6 faces on a cube then we divide it.

300 ÷ 6 = 50.

So exactly 50 times.

Hope this helps :)
7 0
3 years ago
Qual é o valor de 2 elevado a terceira potencia
shusha [124]
A resposta é oito. :))))))
4 0
3 years ago
Does this sum converge: show steps
ehidna [41]

Answer:

Yes

Step-by-step explanation:

\sum_{n=1}^{\infty} e^{-\sqrt{n} } \\\sum_{n=1}^{\infty} (\frac{1}{e})^{\sqrt{n} }

If we say u = √n, then:

\sum_{u=1}^{\infty} (\frac{1}{e})^{u}

This is a geometric series.  Since |1/e| < 1, the series converges.

6 0
4 years ago
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