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Black_prince [1.1K]
2 years ago
12

If a regression analysis shows an R factor of 0.15, it is safe to assume a perfect positive relationship between cost and volume

. a strong negative relationship between cost and volume. a strong positive relationship between cost and volume. a very weak relationship between cost and volume.
Mathematics
1 answer:
saw5 [17]2 years ago
7 0

Answer:

a very weak relationship between cost and volume

Step-by-step explanation:

The R factor is used to access the strength of the relationship between a dependent and independent variable. The R factor ranges between - 1 and 1. With negative values depicting a negative linear relationship and positive values meaning a positive relationship. The closer the R factor is to - 1 or + 1, the greater the strength, a value of 0 means, no correlation exists.

Hence, a R factor of 0.15 depicts a positive but very weak relationship between cost and volume as the R value is close to 0.

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nikklg [1K]

Answer:

56 packs

Step-by-step explanation:

1) (14*24 ) - packets of macaroni altogether.

2) repack into packs of 6.

(14*24)/6 = 56 packs

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3 years ago
Each serving of a cereal is 80 calories.which expression can be used to find the number of calories In 3 servings
valkas [14]

Answer:

80\times3

Step-by-step explanation:

Based on the given conditions, formulate:  80\times3

Calculate the product or quotient: 240

get the result: 240

Answer: 240

To find this answer, we had to use the expression 80 * 3, therefore making it the answer.

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2 years ago
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Part B
alisha [4.7K]

Question:

Consider ΔABC, whose vertices are A (2, 1), B (3, 3), and C (1, 6); let the line segment  AC represent the base of the triangle.

(a)  Find the equation of the line passing through B and perpendicular to the line AC

(b)  Let the point of intersection of line AC with the line you found in part A be point D. Find the coordinates of point D.

Answer:

y = \frac{1}{5}x + \frac{12}{5}

D = (\frac{43}{26},\frac{71}{26})

Step-by-step explanation:

Given

\triangle ABC

A = (2,1)

B = (3,3)

C = (1,6)

Solving (a): Line that passes through B, perpendicular to AC.

First, calculate the slope of AC

m = \frac{y_2 - y_1}{x_2 - x_1}

Where:

A = (2,1) --- (x_1,y_1)

C = (1,6) --- (x_2,y_2)

The slope is:

m = \frac{6- 1}{1 - 2}

m = \frac{5}{-1}

m = -5

The slope of the line that passes through B is calculated as:

m_2 = -\frac{1}{m} --- because it is perpendicular to AC.

So, we have:

m_2 = -\frac{1}{-5}

m_2 = \frac{1}{5}

The equation of the line is the calculated using:

m_2 = \frac{y_2 - y_1}{x_2 - x_1}

Where:

m_2 = \frac{1}{5}

B = (3,3) --- (x_1,y_1)

(x_2,y_2) = (x,y)

So, we have:

\frac{1}{5} = \frac{y - 3}{x - 3}

Cross multiply

5(y-3) = 1(x - 3)

5y - 15 = x - 3

5y  = x - 3 + 15

5y  = x +12

Make y the subject

y = \frac{1}{5}x + \frac{12}{5}

Solving (b): Point of intersection between AC and y = \frac{1}{5}x + \frac{12}{5}

First, calculate the equation of AC using:

y = m(x - x_1) + y_1

Where:

A = (2,1) --- (x_1,y_1)

m = -5

So:

y=-5(x - 2) + 1

y=-5x + 10 + 1

y=-5x + 11

So, we have:

y=-5x + 11 and y = \frac{1}{5}x + \frac{12}{5}

Equate both to solve for x

i.e.

y = y

-5x + 11 = \frac{1}{5}x + \frac{12}{5}

Collect like terms

-5x -\frac{1}{5}x = \frac{12}{5} - 11

Multiply through by 5

-25x-x = 12 - 55

Collect like terms

-26x = -43

Solve for x

x = \frac{-43}{-26}

x = \frac{43}{26}

Substitute x = \frac{43}{26} in y=-5x + 11

y = -5 * \frac{43}{26} + 11

y =  \frac{-5 *43}{26} + 11

Take LCM

y =  \frac{-5 *43+11 * 26}{26}

y =  \frac{71}{26}

Hence, the coordinates of D is:

D = (\frac{43}{26},\frac{71}{26})

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Answer:

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Step-by-step explanation:

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