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Black_prince [1.1K]
3 years ago
12

If a regression analysis shows an R factor of 0.15, it is safe to assume a perfect positive relationship between cost and volume

. a strong negative relationship between cost and volume. a strong positive relationship between cost and volume. a very weak relationship between cost and volume.
Mathematics
1 answer:
saw5 [17]3 years ago
7 0

Answer:

a very weak relationship between cost and volume

Step-by-step explanation:

The R factor is used to access the strength of the relationship between a dependent and independent variable. The R factor ranges between - 1 and 1. With negative values depicting a negative linear relationship and positive values meaning a positive relationship. The closer the R factor is to - 1 or + 1, the greater the strength, a value of 0 means, no correlation exists.

Hence, a R factor of 0.15 depicts a positive but very weak relationship between cost and volume as the R value is close to 0.

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A jogger runs 140 m due west, then changes direction for the second leg of her run. At the end of the run, she is 374 m away fro
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Answer:

The length of her second displacement = 247.12 m.

The direction of her second displacement = 31.24° from west.

Step-by-step explanation:

As per the question,

From the figure as drawn below,

Let the starting point be O. After running 140 m due west, she reached at point A.

∴ OA = 140 m

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By using the cosine rule in triangle OAP

cos \theta = \frac{OA^{2}+OP^{2}-AP^{2}}{2\times OA\times OP}

After putting the given value, we get

cos 20= \frac{140^{2}+374^{2}-x^{2}}{2\times 140\times 374}

x^{2}=140^{2}+374^{2} - 2\times 140\times 374\times cos 20

  ∴ x = 247.12 m  

Hence,the length of her second displacement = 247.12 m.

Again,

By using the cosine rule in triangle OAP, we get

cos \alpha = \frac{OA^{2}+AP^{2}-OP^{2}}{2\times OA\times AP}

After putting the given value, we get

cos \alpha = \frac{140^{2}+247.12^{2}-374^{2}}{2\times 140\times 247.12}

∴ α = 148.759°

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