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Lorico [155]
3 years ago
8

Line segments XY and ZY are tangent to circle O.

Mathematics
2 answers:
REY [17]3 years ago
3 0
It would be an Isosceles triangle
vlabodo [156]3 years ago
3 0

Combine points X and O to get segment XO and combine points Z and O to get segment ZO. Segments XO and ZO are radii of the given circle, then they are congruent. Thus, the triangle XOZ is isosceles, that gives you \angle OXZ\cong \angle OZX.

Since segments XY and YZ are tangent to the circle, then m\angle YXO=m\angle YZO=90^{\circ}.

Consider angles ∠ZXY and ∠XZY:

m\angle ZXY=m\angle OXY-m\angle OXZ,\\m\angle XZY=m\angle OZY-m\angle OZX.

Taking into account that

m\angle OXY=m\angle OZY,\\ m\angle OXZ=m\angle OZX,

you have

m\angle ZXY=m\angle XZY.

If twoo angles adjacent to the side are congruent, then this side is a base of isosceles triangle.

Answer: correct choice is B.

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In the diagram below, we have ST parallel to QR. angle P= 40 degrees, and angle Q= 35 degrees. Find the measure of angles STR in
Drupady [299]

Answer:

m\angle S = 35^\circ, \ m\angle T = 105^\circ,\ m\angle R = 105^\circ

Step-by-step explanation:

<u>Similar Triangles</u>

Lines ST and QR are parallel. Thus, angles S and Q are congruent, and angles T and R are congruent.

Considering the triangle PQR, the sum of its internal angles must be 180°:

m\angle P + m\angle Q + m\angle R = 180^\circ

Substituting the known values:

40^\circ + 35^\circ + m\angle R = 180^\circ

Solving for R:

m\angle R = 180^\circ - 40^\circ - 35^\circ

m\angle R = 105^\circ

Angles S and Q are congruent, thus

m\angle S = 35^\circ

Angles T and R are congruent, thus

m\angle T = 105^\circ

Summarizing:

\mathbf{m\angle S = 35^\circ, \ m\angle T = 105^\circ,\ m\angle R = 105^\circ}

7 0
3 years ago
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Can someone please simplify 6r times s times 4rt?
Ahat [919]
6r × s × 4rt = (6 × 4)(r × r)(st) = 24r²st
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3 years ago
What's 1+1 will mark branleyist
Oksana_A [137]

Answer:2

Step-by-step explanation:

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The two data sets show random samples of the costs, in dollars, of cars purchased at two dealerships yesterday.
hichkok12 [17]
A) The mean of set 1 is 53,800, while the mean of set 2 is 38,600. The median of set 1 is 42,000, while the median of set 2 is 28,000.
B) The median is a more accurate estimate, because each set has 1 particularly large outlier which heavily skews the mean. In each set, the mean is actually higher than 4 out of the 5 data points, which is not very accurate in describing how much the typical car costs.
7 0
3 years ago
The data show the traveler spend- ing in billions of dollars for a recent year for a sample of the states. Find the range, varia
Svetllana [295]

Solution :

Given data :

20.1     33.5     21.7      58.4     23.2     110.8     30.9

24.0    74.8     60.0

n = 10

Range : Arranging from lowest to highest.

20.1,   21.7,   23.2,    24.0,   30.9,    33.5,    58.4,    60.0,    74.8,   110.8

Range = low highest value - lowest value

           = 110.8 - 20.1

           = 90.7

Mean = $\frac{\sum x}{n}$

         $=\frac{20.1+21.7+23.2+24.0+30.9+33.5+58.4+60.0+74.8+110.8}{10}$

          $=\frac{457.4}{10}$

         $=45.74$

Sample standard deviation :

$S=\sqrt{\frac{1}{n-1}\sum(x-\mu)^2}$

$S=\sqrt{\frac{1}{10-1}(20.1-45.74)^2+(21.7-45.74)^2+(23.2-45.74)^2+(24.0-45.74)^2+(30.9-45)^2}$  

      \sqrt{(33.5-45.74)^2+(58.4-45.74)^2+(60.0-45.74)^2+(74.8-45.74)^2+(110.8-45.74)^2}

$S=\sqrt{\frac{1}{9}(657.4+577.9+508.0+472.6+220.2+149.8+160.2+203.3+844.4+4232.8)}$$S=\sqrt{\frac{1}{9}(8026.96)}$

$S=\sqrt{891.88}$

S = 29.8644

Variance = S^2

               =(29.8644)^2

               = 891.8823

6 0
3 years ago
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