There's not enough information, such as how big was the class.
150 x 24 = 3,600, so I would say yes.
Correct answer is d i believe
Answer:
Total Surface Area: A = 88 square cm
Step-by-step explanation:
Volume V = 48 cubic cm
So this cuboidal box is actually a rectangular prism.
V = L * W* H
L = length, W = breadth, H= height
With L: W : H = 3: 2: 1
L:W = 3: 2
W: H = 2: 1
L/W = 3/2, L = (3/2)*W
W/H = 2/1 , W = 2*H
L = (3/2)*(2H) = 3H
So : V = L * W * H = (3H) * (2H) * H = 6 * H^3
48 = 6 * H^3
48/6 = 8 = H^3
H = cube-root(8) = 2 cm
so ...
W = 2*H = 2*2 = 4 cm
L = (3/2)*W = (3/2)* 4 = 6 cm
Total Surface Area: A = 2*LW + 2*LH + 2*WH
A = 2*(6 * 4) + 2*(6 * 2) + 2*(4 * 2)
A = 2*24 + 2*12 + 2*8
A = 48 + 24 + 16
A = 48 + 40
A = 88 square cm
Answer:
The correct option for this is C.) The mean and median age are more likely to be the same for the students in Math 1.
Step-by-step explanation:
i) The median age of the students is Math 1 is less than the median age of the students in Math 2.
This statement is NOT TRUE as the median age of students in Math 1 = median age of students in Math 2 = 19
ii) The mean and median age are most likely the same for both sets of data.
This statement is NOT TRUE. The mean age of students in Math 2 should be greater than mean age of students in Math 1.
iii) The mean and median age are more likely to be the same for the students in Math 1.
This statement is TRUE.
Answer:
1/89
Step-by-step explanation: