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Lorico [155]
3 years ago
8

Line segments XY and ZY are tangent to circle O.

Mathematics
2 answers:
REY [17]3 years ago
3 0
It would be an Isosceles triangle
vlabodo [156]3 years ago
3 0

Combine points X and O to get segment XO and combine points Z and O to get segment ZO. Segments XO and ZO are radii of the given circle, then they are congruent. Thus, the triangle XOZ is isosceles, that gives you \angle OXZ\cong \angle OZX.

Since segments XY and YZ are tangent to the circle, then m\angle YXO=m\angle YZO=90^{\circ}.

Consider angles ∠ZXY and ∠XZY:

m\angle ZXY=m\angle OXY-m\angle OXZ,\\m\angle XZY=m\angle OZY-m\angle OZX.

Taking into account that

m\angle OXY=m\angle OZY,\\ m\angle OXZ=m\angle OZX,

you have

m\angle ZXY=m\angle XZY.

If twoo angles adjacent to the side are congruent, then this side is a base of isosceles triangle.

Answer: correct choice is B.

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In class of 24 students teaching students sold over 150 each and the rest of the car sold about 60 raffle tickets each did the c
Debora [2.8K]
There's not enough information, such as how big was the class.
150 x 24 = 3,600, so I would say yes.
6 0
4 years ago
Which expression is equivalent to -6x^2 - 11x - 4?
Mekhanik [1.2K]
Correct answer is d i believe
4 0
3 years ago
Check thepic plzz first answer brainliest
aleksandr82 [10.1K]

Answer:

Total Surface Area:  A = 88 square cm

Step-by-step explanation:

Volume V = 48 cubic cm

So this cuboidal box is actually a rectangular prism.

V =  L * W* H

L = length,   W = breadth,   H= height

With  L: W : H = 3: 2: 1

L:W = 3: 2

W: H = 2: 1

L/W  = 3/2,    L = (3/2)*W

W/H = 2/1 ,    W = 2*H

L = (3/2)*(2H) =  3H

So  :   V = L * W * H =  (3H) * (2H) * H  = 6 * H^3

48  =  6 * H^3

48/6 = 8 = H^3

H = cube-root(8) =  2 cm

so  ...

W = 2*H = 2*2 = 4 cm

L = (3/2)*W = (3/2)* 4 = 6 cm

Total Surface Area:  A = 2*LW  + 2*LH + 2*WH

A = 2*(6 * 4)  +  2*(6 * 2)  + 2*(4 * 2)

A = 2*24  + 2*12 + 2*8

A = 48 + 24 + 16

A = 48 + 40

A = 88 square cm

4 0
4 years ago
The box plots below show the ages of college students in different math courses.
Slav-nsk [51]

Answer:

The correct option for this is C.) The mean and median age are more likely to be the same for the students in Math 1.

Step-by-step explanation:

i) The median age of the students is Math 1 is less than the median age of the students in Math 2.

This statement is NOT TRUE as the median age of students in Math 1 = median age of students in Math 2 = 19

ii) The mean and median age are most likely the same for both sets of data.

   This statement is NOT TRUE. The mean age of students in Math 2 should be greater than mean age of students in Math 1.

iii) The mean and median age are more likely to be the same for the students in Math 1.

  This statement is TRUE.

8 0
3 years ago
Read 2 more answers
8/712 what is the answer for this?
Alisiya [41]

Answer:

1/89

Step-by-step explanation:

3 0
3 years ago
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