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ladessa [460]
4 years ago
10

Combustion and corrosion are similar reactions because they both... A) release Carbon Dioxide as a product B) release oxygen as

a product C) require oxygen as a reactant D) Have a metal as a reactant
Chemistry
1 answer:
Anit [1.1K]4 years ago
6 0

Answer:

<em>B. release oxygen as a product </em>

Explanation:

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Which of these are equal to 3.01 x 1023 particles 76.9 g of diatomic iodine (I2) 79.9 g of diatomic bromine (Br2) 6 g of carbon
solmaris [256]
To determine which is the correct answer, we convert the mass of the compounds into units of particles of the compound. We use the molar masses and the Avogadro's number. We do as follows:

<span>76.9 g I2  (1 mol / 253.81 g) (6.022x10^23 particles / 1 mol ) = 1.82x10^23

79.9 g Br2 (1 mol / 159.81 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>

6 g C (1 mol / 12 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>

13.01 g CH4 ( 1 mol / 16.04 g )</span>(6.022x10^23 particles / 1 mol ) = 4.88x10^23 particles

Therefore, the answers are Br2 and C.
3 0
3 years ago
SnO2 + C → Sn + СО balance​
rewona [7]

Answer:

Tin(IV) Oxide + Carbon = Tin + Carbon Monoxide

Explanation:

7 0
3 years ago
Read 2 more answers
An element with 7 valence electrons would be a
Sunny_sXe [5.5K]

Answer:

The Group 7A elements have seven valence electrons in their highest-energy orbitals (ns2np5). This is one electron away from having a full octet of eight electrons, so these elements tend to form anions having -1 charges, known as halides: fluoride, F-; chloride, Cl-, bromide, Br-, and iodide, I-.

...

Group 7A — The Halogens.

(7)

(8)

(9)

(10)

Explanation:

here is your answer hope you will enjoy and mark me as brainlist

thank you

6 0
2 years ago
Which statement is true about energy changes?
Sindrei [870]

Answer:

D

Explanation:

energy can not be created or destroyed it can only be transferred or changed to one form to another.

7 0
4 years ago
g How many grams of beryllium are needed to produce "11.5" g of hydrogen gas?Be(s) + 2H 2 O(l) → Be(OH) 2 (aq) + H 2 (g)
slega [8]

Answer:

m_{Be}=51.3gBe

Explanation:

Hello,

In this case, with the given chemical reaction:

Be(s) + 2H_2 O(l) \rightarrow Be(OH)_ 2 (aq) + H _2 (g)

We can notice a 1:1 mole ratio between hydrogen gas and beryllium metal, therefore, beryllium requirement is computed as shown below:

m_{Be}=11.5gH_2*\frac{1molH_2}{2.02gH_2} *\frac{1molBe}{1molH_2} *\frac{9.01gBe}{1molBe}\\ \\m_{Be}=51.3gBe

Regards.

6 0
3 years ago
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