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Anastasy [175]
4 years ago
11

Na2CO3 covalent or ionic

Chemistry
2 answers:
snow_tiger [21]4 years ago
7 0
It is ionic since it contains both a metal and non-metal.
Covalent substances do not contain any metallic elements at all

Hope this helps :)
Otrada [13]4 years ago
4 0
NaCO3 is a iconic bond.
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What’s the difference between snow and water
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A hydrocarbon is burnt completely to give 3.447g of
goblinko [34]

<u>Answer:</u> The empirical formula for the given compound is CH_2

<u>Explanation:</u>

The chemical equation for the combustion of compound having carbon, hydrogen, iron and oxygen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y'  are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=3.447g

Mass of H_2O=1.647g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 3.447 g of carbon dioxide, \frac{12}{44}\times 3.447=0.940g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 1.647 g of water, \frac{2}{18}\times 1.647=0.183g of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.940g}{12g/mole}=0.0783moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.183g}{1g/mole}=0.183moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0783 moles.

For Carbon = \frac{0.0783}{0.0783}=1

For Hydrogen = \frac{0.183}{0.0783}=2.34\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 2

Hence, the empirical formula for the given compound is CH_2

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