1.5b=11-9
1.5b=2
b=1.3 repeating or 1 1/3
C = 3.5t....when t = 15
c = 3.5(15)
c = 52.50 <==
If you would like to find the quotient of 2 1/4 and 5/8, you can calculate this using the following steps:
2 1/4 = 9/4
2 1/4 / 5/8 = 9/4 / 5/8 = 9/4 * 8/5 = 18/5 = 3 3/5
The correct result would be 3 3/5.
Answer: the rate at which the distance between the boats is increasing is 68 mph
Step-by-step explanation:
The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.
Let x represent the length the shorter leg(south) of the right angle triangle.
Let y represent the length the longer leg(east) of the right angle triangle.
Let z represent the hypotenuse.
Applying Pythagoras theorem
Hypotenuse² = opposite side² + adjacent side²
Therefore
z² = x² + y²
To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes
2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1
One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that
dx/dt = 32
dy/dt = 60
Distance = speed × time
Since t = 0.5 hour, then
x = 32 × 0.5 = 16 miles
y = 60 × 0.5 = 30 miles
z² = 16² + 30² = 256 + 900
z = √1156
z = 34 miles
Substituting these values into equation 1, it becomes
2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60
68dz/dt = 1024 + 3600
68dz/dt = 4624
dz/dt = 4624/68
dz/dt = 68 mph
Answer:
y = x^2 - 4x - 6.
Step-by-step explanation:
The roots are 2 + √10 and 2 - √10, so in factor form we have:
(x - (2 + √10))(x - (2 - √10))
= ( x - 2 - √10)(x - 2 + √10)
= x^2 - 2x + √10x - 2x + 4 - 2√10 - √10x + 2√10 - √100
= x^2 -4x + 4 - 10
= x^2 - 4x - 6.
