Question

6v^2+24=0 find roots of equation

Answer 1

Step-by-step explanation:

$6 {v}^{2} + 24 = 0 \\ \\ \therefore \: 6 {v}^{2} = - 24 \\ \\ \therefore \: {v}^{2} = \frac{ - 24}{6} \\ \\ \therefore \: {v}^{2} = - 4\\ \\ \therefore \: {v}^{2} = 4\times - 1\\ \\ \therefore \: {v} =\pm \sqrt {4} \times \sqrt{- 1} \\ \\ \therefore \: {v} =\pm 2 \times i\\ \\ \therefore \: {v} = \pm \sqrt{2} i$