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hammer [34]
4 years ago
10

6v^2+24=0 find roots of equation

Mathematics
1 answer:
Fed [463]4 years ago
8 0

Step-by-step explanation:

6 {v}^{2}  + 24 = 0 \\  \\  \therefore \: 6 {v}^{2}  =  - 24  \\  \\ \therefore \: {v}^{2}  =   \frac{ - 24}{6} \\  \\ \therefore \: {v}^{2}  =    - 4\\  \\ \therefore \: {v}^{2}  =    4\times - 1\\  \\ \therefore \: {v}  =\pm    \sqrt {4} \times \sqrt{- 1} \\  \\ \therefore \: {v}  =\pm    2 \times i\\  \\ \therefore \: {v} =     \pm \sqrt{2} i

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