Answer:
So we need to add 13.46 gr of ice in order to reach the final equilibrium temperature of 49 C
Explanation:
For this case we need to use the fact that the sum for all the heats involved in the system are 0, since we assume an equilibrium state.
Data given
mass of the porcelain cup
the specific heat for the porcelain cup
initial temperature for the coffee and the porcelain cup.
Volume of the coffee.
We can convert this to m^3 and we got 0.000161m^3 and assuming the density fot the coffee equal to the water 1 Kg/m^3 the mass would be:
Specific heat for the coffee
mass of ice required
equilibrium temperature
represent the latent heat of fusin since the ice change the state to liquid.
Solution to the problem
Using this formula:
We have this:
Now we can replace and we have this:
And now we can solve for and we have:
So we need to add 13.46 gr of ice in order to reach the final equilibrium temperature of 49 C
Cardiac, smooth, and skeletal. cardiac muscle cells are located in the walls of the heart and appear striated and are under involuntary control. smooth muscle fibers are located in walls of hollow visceral organs except the heart they also appear striated. skeleton muscle is found between bones and uses tendons to connect to the epimysium to the periosteum, or the outer covering of bone. skeletal muscle is shaped and adapted in many ways.
(please mark me brainliest!)
Was related to my mother.
The distress call had given the ship's position.
It isn't the first time I have cooked.
The head of our commission made a motion<span> that we rewrite the constitution.</span>
First, let us assign the variables
y = 0.90 m, x= 15 m,
= 2.80 m
s= required
The vertical component of the trajectory is in uniformly accelerated motion. The equation is:
, while the horizontal component is
. Also,
since the object starts from rest (with respect to the downward motion). a is negative because it is moving downwards (a = -9.81 m/s^2). Substituting,
The magnitude of v0, which is speed (s), is equal to 24.1 m/s
Answer:
19.3
Explanation:
Assuming we have to find Specific gravity of gold.
As we know that specific gravity is defined as the ratio of weight of the object and weight of the water displaced by the object
so it is given by
specific gravity = weight of the object/weight of the water displaced
now we have
weight of the object = (density)(volume)g
weight of object = (19.3)(0.55)g
now weight of the liquid displaced is given by
weight of water displaced = (1 g/cm^3)(0.55ml)g
now we have
specific gravity = (19.3×0.55)/(1×0.55)
specific gravity= 19.3