What is the maximum capacity of an analog circuit with a bandwidth of 4000 hz using qam?

alukav5142 [94]

Answer:

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4 0

4 years ago

A wire has a resistance of 27.2 ohms. It is melted down, and from the same volume of metal a new wire is made that is 3 times lo

solmaris [256]

Answer:

81.6 ohm

Explanation:

For a cable type conductor, the resistance is given by the following formula:

$R=\rho \frac{l}{S}$

Where:

$\rho=Material\hspace{3}resistivity\\l=Cable\hspace{3}length\\S=Cable\hspace{3}cross\hspace{3}section$

The problem doesn't give us additional information about resistivity or the cross section of the wire, so let's assume:

$S=constant\\\rho=constant$

Then, in this case, the resistance of the cable depends only on the length. Therefore, if its resistance was originally 27.2 ohms, if we triple its length, it makes sense that its new resistance is three times the original. Thus:

$R=3*(27.2)=81.6ohm$

5 0

3 years ago

A solution of phosphoric acid was made by dissolving 10.0 g H3PO4 in 100.0 mL water. The resulting volume was 104 mL. Calculate

OLEGan [10]

Answer:

density is 1.057 g/mL

mole fraction is 0.0180

molarity is 0.98 mol/L

mole fraction is 0.0180

Explanation:

Given data

acid mass = 10 g

water volume = 100 mL

total volume = 104 mL

density = 1 g/cm³

to find out

the density, mole fraction, molarity, and molality

solution

first we calculate the density that is = total mass g / volume of solution mL

total mass = mass of H3PO4 + water mass

so water mass = density x volume

water mass = 100 ml x 1.0 g/cm3

water mass = 100 g

so total mass = 110.00 g

so that

density = total mass g / volume of solution mL

density = 110 / 104 = 1.057 g/mL

now we calculate no of moles in solvent i.e = mass H2O / mlar mass H2O

no of moles in solvent = 100/18.015 = 5.55 moles

and no of moles in solute i.e = mass of H3PO4 / mlar mass in H3PO4

moles in solute i.e = 10/ 97.994 = 0.102 moles

so total moles is 5.55 + 0.102 = 5.652 moes

so now mole fraction = no of moles in solute / total moes

mole fraction = 5.55 / 5.65

mole fraction is 0.0180

now we calculate first

mole fraction in solute and solvent that is

mole fraction in solute = no of moles in solute/ total moles

mole fraction in solute = 0.102 /5.65

mole fraction in solute is 0.0180

and mole fraction in solvent that = no of moles in solvent/ total moles

mole fraction in solvent that = 5.55/ 5.65

mole fraction in solvent that is 0.982

so molarity = no of moles of solute / volume

molarity = 0.102/0.104

molarity is 0.98 mol/L

and molality is = no of moles of solute / mass

molality = 0.102 / 100

molality is 1.02 mol/kg

6 0

3 years ago

Which describes an image that a concave mirror can make?

Zigmanuir [339]

An image that a concave mirror can make is that it <span>can form a real image that is projected out in front of the mirror. </span>A concave mirror<span> is a mirror that is curved inward in the middle. Using the mirror equation, you can deal with concave mirrors. It's like you're looking into a cave when try to look in a concave mirror.</span>

6 0

3 years ago

Where is the centre of mass of a system of two particles is situated?

Sever21 [200]

Answer:

In a two particle system, the center of mass lies on the center of the line joining the two particles.

4 0

3 years ago