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Olin [163]
4 years ago
13

What is the instantaneous speed of the object after the five seconds?

Physics
1 answer:
OverLord2011 [107]4 years ago
7 0

Answer:

12.5 m/s

Explanation:

In a acceleration time graph the area under the curve gives the change in velocity of the object. Here object starts at rest and therefore initial velocity is 0. After 5 seconds acceleration is 5m/s2.

change in velocity=area under the curve

change in velocity= 0.5*acceleration* change in time

v-0=0.5*5*5

v=12.5 m/s

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Which of Mendel principles would apply to mating two organisms that have two different alleles for three different traits
ozzi

Answer:

Law of independent assortment

Explanation:

This is because law of independent assortment state that alleles of two or more genes when two organisms mate will be inherited or pass down to gametes which are in one way or the other independent of each other or each of the alleles. Therefore parent can have up to three different traits and the alleles can be inherited by the gametes.

5 0
3 years ago
Read 2 more answers
The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. The tangential speed of the satellite, writ
LenaWriter [7]

The orbital period of the satellite[T] is given as 2*10^{6} S.

The radius of the satellite is given [R] 2.5*10^{12} m.

we are asked here to calculate the tangential speed of the satellite.

Before going to get the solution first we have understand the tangential speed.

The tangential speed of a satellite is given as the speed required to keep the satellite along the orbit. If satellite speed is less than tangential speed,there is the chance of it falling down towards earth. If it is more,then it will deviate from it orbit and can't stick to the orbit further.In a simple way  the tangential speed is the linear speed of an object in a circular path.

Now we have to calculate the tangential speed [V].

Mathematically the tangential speed [V]   written as -

                                V=\frac{2\pi R}{T}

where T is the time period of the satellite and R is the radius of the satellite.

                        V=\frac{2*3.14*10^{12} }{2*10^{6} }

                               = 7.85*10^{6} m/s

There is also another way through which we can get  the solution as explained below-

We know that the tangential speed of a satellite V=\sqrt{\frac{GM}{R^{2} } }

where G is the gravitational constant and M is the mas of central object.

But we know that g=\frac{GM}{R^{2} }

                               ⇒GM=gR^{2}  where g is the acceleration due to gravity of that central object.


Hence    V=\sqrt{\frac{gR^{2} }{R} }

               ⇒   V=\sqrt{gR}

By knowing the value of g due to that central object we can also calculate its tangential speed.

                           

 




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3 years ago
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A TV with a power rating of 267 W uses 1.9 kWh in one day. How many hours was the TV during that day?
Aleonysh [2.5K]
1.9kWh/0.267kW = 7.11 hours
4 0
3 years ago
Is the sun considered a star?
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Yes it is because it has all the characteristics of one
The sun is unremarkable
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3 years ago
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What type of seismic waves travel through Earth?
ycow [4]

Answer:d. Ground waves

Explanation:A P-wave is one of the two main types of seismic waves. P-waves travel faster than other seismic waves and hence are the first signal from an earthquake to arrive at any affected location or at a seismograph

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