Answer:
The speed of the spider is v = (2g*L*(1-cosθ))^1/2
Explanation:
using the energy conservation equation we have to:
Ek1 + Ep1 = Ek2 + Ep2
where
Ek1 = kinetic energy = 0
Ep1 = potential energy = m*g*L*cosθ
Ek2 = (m*v^2)/2
Ep2 = m*g*L
Replacing, we have:
0 - m*g*L*cosθ = (m*v^2)/2 - m*g*L
(m*v^2)/2 = m*g*L*(1-cosθ)
v^2 = 2g*L*(1-cosθ)
v = (2g*L*(1-cosθ))^1/2
Answer:
(a) Z = 48.3 Ω
(b) cos ∅ = 0.455
(c) Irms = 10.35 A
(d) C = 74.02 μF
(e) Irms = 4.44 A
Explanation:
Power (P) = 2.36 kW
Frequency (f) = 50 Hz
RMS Voltage (Vrms) = 500 V
Resistance (R) = 22 Ω
Inductive Reactance (XL) = 43 Ω
(a) to calculate the total impedance, use the formula:
Z = √(R² + XL²)
= √((22)² + (43)²)
= √2333
Z = 48.3 Ω
(b) To calculate the plant's power factor, we will use the formula:
cos ∅ = R/Z
= 22/48.3
cos ∅ = 0.455
(c) To calculate the RMS current used by the plant, divide the RMS voltage value by the impedance of the plant.
Irms = Vrms/Z
= 500/48.3
Irms = 10.35 A
(d) For the power factor to become unity, the inductive reactance must be equal to the capacitive reactance i.e. Xc = XL
Xc = XL
1/(2πfC) = XL
1/(2πfXL) = C
C = 1/(2π*50*43)
= 7.402 x 10⁻⁵
C = 74.02 μF
(e) P = Vrms*Irms*cos∅
Irms = P/Vrms*cos∅
= 2.22 x 10³/500*1
Irms = 4.44 A
Answer:
I=VRS=9V90Ω=0.1A
Explanation:
The equivalent resistance is the algebraic sum of the resistances (Equation 10.3. 2): RS=R1+R2+R3+R4+R5=20Ω+20Ω+20Ω+20Ω+10Ω=90Ω. The current through the circuit is the same for each resistor in a series circuit and is equal to the applied voltage divided by the equivalent resistance
Answer:
100 degrees Celsius
Explanation:
Water starts to boil at 100 degrees celcius or 212 degrees fahrenheit.
The equivalent capacitance (
) of an electrical circuit containing four capacitors which are connected in parallel is equal to: A. 21 F.
<h3>The types of circuit.</h3>
Basically, the components of an electrical circuit can be connected or arranged in two forms and these are;
<h3>What is a parallel circuit?</h3>
A parallel circuit can be defined as an electrical circuit with the same potential difference (voltage) across its terminals. This ultimately implies that, the equivalent capacitance (
) of two (2) capacitors which are connected in parallel is equal to the sum of the individual (each) capacitances.
Mathematically, the equivalent capacitance (
) of an electrical circuit containing four capacitors which are connected in parallel is given by this formula:
Ceq = C₁ + C₂ + C₃ + C₄
Substituting the given parameters into the formula, we have;
Ceq = 10 F + 3 F + 7 F + 1 F
Equivalent capacitance, Ceq = 21 F.
Read more equivalent capacitance here: brainly.com/question/27548736
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