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jek_recluse [69]
4 years ago
11

Suppose 2/3 of people surveyed like the new trial flavor of chips. How many people would you have to select randomly, on average

, in order to get 10 people who DO NOT like the new trial flavor?
Mathematics
1 answer:
mixas84 [53]4 years ago
5 0

Answer:

To me it seems like 30

Step-by-step explanation:

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What 9y+9x-10a-10c-10b
KIM [24]
Hey man just use photo math
4 0
4 years ago
Determine the multiplicity of the roots of the function k(x) = x(x + 2)3(x + 4)2(x − 5)4. 0, -2, -4, 5
Sergeu [11.5K]

Answer:

The polynomial function k(x)=x(x+2)^3(x+4)^2(x-5)^4

To determine the multiplicity of 0, -2, -4, 5.

The multiplicity of a root is the number of times the root appears.

First find the root of the equation, set the function equals to zero.

x(x+2)^3(x+4)^2(x-5)^4=0

therefore, the root of this function are, x=0,-2, -4, 5

To find the multiplicity of the roots:

A factor of x would have a root at x=0 with multiplicity of 1

similarly,  x=-2 with multiplicity of 3

x=-4 with multiplicity of 2

x=5 with multiplicity of 4.



4 0
3 years ago
Read 2 more answers
What are the limits of integration if the summation the limit as n goes to infinity of the summation from k equals 1 to n of the
Fofino [41]

Answer:

\int_{2}^{9}x^2 dx so the limits are 2 and 9

Step-by-step explanation:

We want to express \lim_{n\rightarrow \infty} \sum_{k=1}^n\frac{7}{n}(2+\frac{7k}{n})^2 as a integral. To do this, we have to identify \sum_{k=1}^n\frac{7}{n}(2+\frac{7k}{n})^2 as a Riemann Sum that approximates the integral. (taking the limit makes the approximation equal to the value of the integral)

In general, to find a Riemann sum that approximates the integral of a function f over an interval [a,b] we can the interval in n subintervals of equal length and approximate the area (integral) with rectangles in each subinterval and them sum the areas. This is equal to

\sum_{k=1}^n f(y_k) \frac{b-a}{n}, where y_k\in[a+(k-1)\frac{b-a}{n},a+k\frac{b-a}{n}] is a selected point of the subinterval.

In particular, if we select the ending point of each subinterval as the y_k, the Riemann sum is:

\sum_{k=1}^n f(a+k\frac{b-a}{n}) \frac{b-a}{n}.

Now, let's identify this in \sum_{k=1}^n\frac{1}{7n}(2+\frac{7k}{n})^2 .

The integrand is x² so this is our function f. When k=n, the summand should be \frac{b-a}{n}f(b)=\frac{b-a}{n}b^2 because the last selected point is b. The last summand is \frac{7}{n}(9)^2 thus b=9 and b-a=7, then 9-a=7 which implies that a=2.

To verify our answer, note that if we substitute a=2, b=9 and f(x)=x² in the general Riemann Sum, we obtain the sum inside the limit as required.

4 0
3 years ago
-1/2x + 3 - 4x + 3/2x
SashulF [63]

Answer:

-6 x (X-1)/2

Step-by-step explanation:

3 0
3 years ago
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Whaqt is the comon GCF of 54 and 27 pls tell me i need to know
4vir4ik [10]
27 since 27 is a factor of 54
6 0
3 years ago
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