7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
Answer:
DE≈16.1
m<E≈60.3
m<D≈29.7
Step-by-step explanation:
Answer:
A boat would need 21 liters to cover the distance of 84 km.
Step-by-step explanation:
Given
A boat can travel 496 km on 124 liters of fuel.
To determine
How much fuel will it need to go 84 km?
It is stated that:
Distance covered in 124 liters of fuel = 496 km
Thus,
Unit rate = 496 km / 124 liters
= 4 km per liter
Thus,
The distance covered in 1 liter = 4km
In order to determine the distance covered in 84 km, all we need is to divide 84 km by 4.
i.e.
The fuel needed to go 84 km = 84 / 4 = 21 liters
Therefore, a boat would need 21 liters to cover the distance of 84 km.
<span>Given that the orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P = a^(3/2).
If Saturn’s orbital period is 29.5 years, then
29.5 = a^(3/2)
a = (29.5)^(2/3) = 9.547
Therefore, Saturn's distance from the sun is 9.547 astronomical units.</span>
Answer:
yes she will
Step-by-step explanation:
im not very sure if it is correct, and if its wrong then im sorry
