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arsen [322]
3 years ago
13

What is the simplified radical form of 369?

Mathematics
1 answer:
Mumz [18]3 years ago
5 0
I'm not sure about the radical from, but the square root is <span>19.2093727123. Hope this helped!
<span><span><span><span>
</span></span></span></span></span>
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Can someone please answer. There is one question. There's a picture thank you!
soldier1979 [14.2K]
<span>The range of Cos(x) is [-1,1]. Therefore the range of ln(Cos(x)) will be the image of [-1,1] using the natural log function. However, the domain of ln(x) is (0,infinity) and the log function is strictly increasing with vertical asymptote at "x=0". Therefore, the range of ln(Cos(x)) will be: 

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8 0
3 years ago
Which angle is formed by a secant and tangent line?
vaieri [72.5K]

Check the picture below.

5 0
3 years ago
Add or subtract 2/4x +1/3
VashaNatasha [74]
Subtract



Explanation:
3 0
1 year ago
Please help i’m so stuck i can’t do calc for the life of me
KATRIN_1 [288]

Answer:

-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}  is the answer. See steps below.

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}\\\\-3x^5+11x^4+33x^3-26x^2-36x-6\\\\\mathrm{and\:the\:divisor\:}x^3+6x^2-3x-5:\\\\\mathrm{Quotient}=\frac{-3x^5}{x^3}=-3x^2\\\\\mathrm{Multiply\:}x^3+6x^2-3x-5\mathrm{\:by\:}-3x^2\:\:\rightarrow\:\:-3x^5-18x^4+9x^3+15x^2\\\\\mathrm{Subtract\:}-3x^5-18x^4+9x^3+15x^2\mathrm{\:from\:}-3x^5+11x^4+33x^3-26x^2-36x-6\mathrm{\:to\:get\:new\:remainder}.\\\\\mathrm{Remainder}=29x^4+24x^3-41x^2-36x-6

=-3x^2+\frac{29x^4+24x^3-41x^2-36x-6}{x^3+6x^2-3x-5}

Repeat the steps and you will reach a point where no further division is possible.

<u />

<u />=-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}<u />

5 0
2 years ago
Please help me with this please and thank you
BartSMP [9]

Answer:

12

Step-by-step explanation:

4x-3x

4*3=12

it is 12

7 0
2 years ago
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