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4 years ago

Please Help!!!

Physics

1 answer:

Semenov [28]4 years ago

3 0

Answer: 4.486N

Explanation:

The Gravitational force of attraction 'F' between two masses m1 and m2 is given by:

F= Gm1m2 / r^2

Where ; r = distance between the bodies

G = gravitational constant = 6.67 × 10^-11

The mass of the earth (m1) = 5.98 × 10^24 kg

Mass of the moon (m2) = 7.35 × 10^22 kg

Mass of rocket (m3) = 1200 kg

the net gravitational force on the rocket from the earth and moon equals

Difference in the gravitational force between the earth and rocket and that exerted between th e moon and rocket.

Net F = (Gm1m3 / r^2) - (Gm2m3) /r^2

Net F = Fa - Fb

Fa = Gm1m3 / r^2 =

(6.67 × 10^-11 × 5.98 × 10^24 × 1200) /(3 × 10^8)^2

(6.67×5.8×1200)/ 9 × 10^(-11 + 24 - 16)

= 5318 × 10^-3 = 5.32N

Fb = Gm2m3 / r^2 =

r = (3.84 × 10^8 - 3.0×10^8) = 0.84 × 10^8

(6.67 × 10^-11 × 7.35 × 10^22 × 1200) /(8.4× 10^7)^2

(6.67×7.35×1.2)/ 70.56 × 10^(-11 + 22 + 3 - 14)

= 0.83375N

Fnet = 5.32N - 0.83375N = 4.48625N

= 4.486N

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3 years ago

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3 years ago

The wheel having a mass of 100 kg and a radius of gyration about the z axis of kz=300mm, rests on the smooth horizontal plane.a.

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Answer:

a) 20 rad/s

b) 6 m/s

Explanation:

b) Force acting on the wheel is 200 N

mass of the wheel is 100 kg

From Newton's second law of motion, F = m × a

Where F is the net force acting on the body

m is mass of the body

a is the acceleration of the body

By substituting the values we get, a = 2 m/s²

As acceleration is constant, we can use the below formula for calculating the final velocity of the object

v = u + a × t

Where v is the final velocity

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t is the time taken

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By substituting the values we get

v = 0 + 2 × 3 = 6 m/s

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Torque acting on the wheel about axis of rotation = 300 mm × 200 N =

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Torque = (Moment of inertia) × (angular acceleration)

Assuming that the mass of spokes of the wheel to be negligible,

Moment of inertia of the wheel about axis of rotation = 100 × 300² × $10^{-6}$ = 9 kg·m²

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60 = 9 × (angular acceleration)

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As angular acceleration of the wheel is constant, we can use the below formula for calculation of final angular speed

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$w_{f}$ is the final angular velocity

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By substituting the values we get

$w_{f}$ = 6·67 × 3 = 20 rad/s

∴ Angular velocity of the wheel after three seconds = 20 rad/s

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4 years ago