Answer:
Law conservation of charge (D)
Explanation:
When the mass is 5.0 cm from its equilibrium point, the percentage of its energy that is kinetic is 75%.
<h3>Total energy of the mass</h3>
The total energy possessed by the mass under the simple harmonic motion is calculated as follows;
U = ¹/₂kA²
where;
- k is the spring constant
- A is the amplitude of the oscillation
<h3>Potential energy of the mass at 5 cm from equilibrium point</h3>
P.E = ¹/₂k(Δx)²
<h3>Kinetic energy of mass</h3>
K.E = U - P.E
K.E = ¹/₂kA² - ¹/₂k(Δx)²
<h3>Percentage of its energy that is kinetic</h3>

Thus, when the mass is 5.0 cm from its equilibrium point, the percentage of its energy that is kinetic is 75%.
Learn more about kinetic energy here: brainly.com/question/25959744
Weight = (mass) x (gravity)
On Earth ...
Weight = (1 kg) x (9.8 m/s^2)
Weight = 9.8 Newtons