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Bumek [7]
3 years ago
5

What is 9+1 no take away Yes please help long answer pls and ty bye bye

Mathematics
2 answers:
Kay [80]3 years ago
4 0

Answer:10

Step-by-step explanation:

Paul [167]3 years ago
3 0
Is this a trick question? if not then 10
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When constructing parallel lines , how can you verify the lines constructed are parallel
tamaranim1 [39]

Answer:

  compare the distance between the lines at one point to the distance between the lines at another point

Step-by-step explanation:

You can construct perpendiculars at different points and compare the distance between the lines at those perpendiculars. The distance between parallel lines is the same everywhere.

8 0
3 years ago
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Verify the identity algebraically:<br> Csc(-x)tanx =-secx
weqwewe [10]

Step-by-step explanation:

Recall that

\sin(-x) = -\sin x

Therefore,

\csc(-x) = \dfrac{1}{\sin(-x)} = -\dfrac{1}{\sin x}

so

\csc(-x)\tan x = \left(-\dfrac{1}{\sin x}\right)\left(\dfrac{\sin x}{\cos x}\right)

\:\:\:\:\:\:\:\:\:= -\dfrac{1}{\cos x} = -\sec x

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3 years ago
Convert into fraction:<br> 0.612<br> the 12 reapeating forever<br> plz help
Charra [1.4K]

Answer:

Step-by-step explanation:

x=0.6121212... (1)

10x=6.121212...   (2)

1000 x=612.121212...   (3)

(3)-(2) gives

990 x=606

330x=202

165x=101

x=(101)/165

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3 years ago
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Can you tell me the answer and explanation of this problem
Lyrx [107]

Answer:

Step-by-step explanation:

The Beg balance means what she was having initially =$154.90

The pay check and deposit are credits on her account so they were added.

The wig, shoes and makeup she bought were debits, so they were subtracted

Closing balance is the amount left after the debits have been subtracted from the credits

3 0
3 years ago
Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon
Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

h(t)=-16t^2+40t+5

we know that

When the ball hits the ground, the height is equal to zero

so

-16t^2+40t+5=0

The formula to solve a quadratic equation of the form

at^{2} +bt+c=0

is equal to

t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+40t+5=0

so

a=-16\\b=40\\c=5

substitute in the formula

t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}

t=\frac{-40\pm\sqrt{1,920}} {-32}

t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec

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therefore

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4 0
3 years ago
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