The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>
Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib
For Addison h=85(1/3)
Subtracting both distances we get
Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
brainly.com/question/1392973
Answer:
42
Step-by-step explanation:
x/3+12 = 26
Multiply everything by 3 to eliminate the fraction
x+36=78
subtract 36 on both sides
x=42
42/3=14
14+12=26
Answer:
(x+1)(x−1)(x+4)(x−4)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Area of the good part= area of whole roof - area of bad part
Since the roof is a square roof, the area will be calculated using the formulae for area of a square
Area of a square =length²
Area of good part =(x+12)²-x²
A= {(x+12)(x+12)} - x²
A = (x²+12x+12x+144) -x²
Open the bracket and rearrange the equation
A= x²-x²+24x+144
A=(24x+144) ft
Answer:
the total distance she traveled is 10 1/5
