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goldenfox [79]
2 years ago
6

A composite figure is made up of a triangular prism on top of a rectangular prism. Which of the following surface area equations

could you use to find the total surface area of the solid? Select all that apply. SA = 2l + l2 SA = 2rh + 2r2 SA = 4r2 SA = r + r2 SA = 2lw + 2lh + 2wh SA = 2B + Ph
Mathematics
2 answers:
Lubov Fominskaja [6]2 years ago
6 0

Answer:In this problem the surface area of the composite figure is equal to the area of the base of the rectangular prism plus the lateral area of the rectangular prism, plus the area of the two triangular faces of triangular prism, plus the area of two rectangular faces of the triangular prism.

Step-by-step explanation:

Aloiza [94]2 years ago
5 0

In this problem the surface area of the composite figure is equal to the area of the base of the rectangular prism plus the lateral area of the rectangular prism, plus the area of the two triangular faces of triangular prism, plus the area of two rectangular faces of the triangular prism. we know that

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Drinking water from a glass. What represents the volume and what represents the surface area?
Sliva [168]

Answer:

As one thing decreases, the other increases

Step-by-step explanation:

8 0
2 years ago
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If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
1 year ago
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
kogti [31]

Answer:

Advance tickets-$15

Same-day tickets-$20

Step-by-step explanation:

let x be the cost of advance tickets and y cost of same-day tickets:

x+y=35\ \ \ \ \  \ \ ...i

Given that there were 40 advance and 25 same-day tickets for a total of $1100:

40x+25y=1100\\\\8x+5y=220\ \ \ \  \ \ \ \ \ \ \ ...ii

#Make x the subject in i and substitute in ii:

x=35-y\\\\\therefore 8x+5y=220, x=35-y\\\\8(35-y)+5y=220\\\\280-8y+5y=220\\\\60=3y\\\\y=20\\\\x=35-y=35-20=15

Hence, advance tickets cost $15 each while same-day tickets cost $20 each.

5 0
3 years ago
Help please picture included
posledela
48 divide 3 = 16 -48 =32 so the answer would be 32 for paulas dog and
16 for carlas dog
8 0
2 years ago
Ypu just need help thxsssss
vampirchik [111]
I think it’s 16 and 8
7 0
2 years ago
Read 2 more answers
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