This is question of probability finding using bayes theorem
It is used to calculate probability of two competing statements
now p(m) = .55
p(~m)= .45
now for basketball for male
p(b|m)=.30
and for female
p(b|~m)=.20
so by bayes theorem
p(m|b)=p(b|m)*p(m)/(p(b|m)*p(m)+p(b|~m)*p(~m))
so answer is E
(.55)(.30) / (.55)(.30) + (.45)(.20)
<h3>
Answer: 0.6</h3>
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Work Shown:
sin(angle) = opposite/hypotenuse
sin(T) = VU/VT
sin(T) = 3/5
sin(T) = 0.6
Answer:
The product of 3 and 4 plus the quotient of 6 and 2 (aka the second one)
Step-by-step explanation:
Answer:
f(-10) = 1,100
Step-by-step explanation:
f(-10) = (-10)^2 - (-10)^3
= 100 - (-1000)
= 1,100
The answer is D because every number after 30 is getting multiplied by 3
