Distance = (rate)(time)
In this problem, note that both girls traveled the same distance.
Karens distance = r * 1.5 hrs we dont know her rate
Nancy distance = 50 * 1 hr we know she started 30 min later
but arrived at the same time
since the distances are equal
r*1.5 = 50 * 1 all you have to do is solve for r
1.5r = 50
r = 50/1.5
r = 33 1/3 miles per hour
-8r^5+23r^3-11r+17
Wasn’t Sure What It Was Asking So Hopefully That Works For You
Answer:
Part 1) Option D. must be an acute angle
Part 2) m∠A=70°
Step-by-step explanation:
Part 1) In triangle ABC, if an exterior angle drawn at vertex C measures 45, then angle B...
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
The measure of an exterior angle at C is equal to the sum of the interior angles at A and B
we have that
45°=m∠A+m∠B
therefore
m∠B < 90°
Angle B must be an acute angle
Part 2)
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
The measure of an exterior angle at B is equal to the sum of the interior angles at A and C
m∠A+m∠C=2m∠C+5
m∠C=m∠A-5 ----> equation A
m∠C=65° ----> equation B
substitute equation B in equation A
65°=m∠A-5
m∠A=(65+5)°=70°
Its D .........................
