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tia_tia [17]
3 years ago
14

Helen wrote the following facts to try to show that division by 0 results in 0. Explain her error.

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0

Helen should of put 0 first, because if you're gonna divide, you need to put the product first, then one of the factoes.

So instead it should be 0÷(-7)=0

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A college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of
Alla [95]

Answer:

80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

Step-by-step explanation:

We are given that a college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of hours they watch per week. The results are provided below;

<u>Hours of TV per week (X)</u>: 6, 14, 13, 6, 16, 10, 19, 4, 5, 5, 18, 8, 7, 14, 8, 8, 9, 12, 6, 5.

Firstly, the Pivotal quantity for 80% confidence interval for the true average is given by;

                                P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of hours of TV watched per week = \frac{\sum X}{n} = 9.65

            s = sample standard deviation = \sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }  = 4.61

            n = sample of people = 20

           \mu = true average number of hours of TV watched per week

<em>Here for constructing 80% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<u>So, 80% confidence interval for the true average, </u>\mu<u> is ;</u>

P(-1.33 < t_1_9 < 1.33) = 0.80  {As the critical value of t at 19 degrees of

                                               freedom are -1.33 & 1.33 with P = 10%}  

P(-1.33 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.33) = 0.80

P( -1.33 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.33 \times {\frac{s}{\sqrt{n} } } ) = 0.80

P( \bar X-1.33 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.33 \times {\frac{s}{\sqrt{n} } } ) = 0.80

<u>80% confidence interval for</u> \mu = [ \bar X-1.33 \times {\frac{s}{\sqrt{n} } } , \bar X+1.33 \times {\frac{s}{\sqrt{n} } } ]

                                         = [ 9.65-1.33 \times {\frac{4.61}{\sqrt{20} } } , 9.65+1.33 \times {\frac{4.61}{\sqrt{20} } } ]

                                         = [8.28 hours, 11.02 hours]

Therefore, 80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

7 0
3 years ago
Rewrite y + 3 = 0 using function notation.
Leni [432]
F(x) basically just substitutes the "y"
so you would bring everything over to one side
y + 3 = 0
subtract 3
y = -3
then 
f(x) = -3

That is B)
3 0
3 years ago
Read 2 more answers
A. (0, -2)
Anastaziya [24]

Answer: D

Step-by-step explanation: edge

3 0
3 years ago
Which of the following rotations around the origin of the triangle with
kramer

Answer:

Step-by-step explanation:

270 degrees

5 0
3 years ago
A machine makes 18 parts per hour if the machine work for 24 hourss how many parts will it have made
sweet-ann [11.9K]

Answer:

432 parts

Step-by-step explanation:

24 x 18 = 432

3 0
2 years ago
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