. Sketch the nucleotide being described: it uses a monosaccharide present in RNA, and a nitrogenous base found only in RNA. Poin
t an arrow to the glycosidic bond.
1 answer:
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Answer : The activation energy for the reaction is, 119.7 J
Explanation :
According to the Arrhenius equation,
or,
where,
= rate constant at 271 K
= rate constant at 281 K =
= activation energy for the reaction = ?
R = gas constant = 8.314 J/mole.K
= initial temperature = 271 K
= final temperature = 281 K
Now put all the given values in this formula, we get:
Therefore, the activation energy for the reaction is, 119.7 J
Answer: At equilibrium , there are 0.274 moles of
Explanation:
Moles of = 0.682 mole
Moles of = 0.440 mole
Volume of solution = 2.00 L
Initial concentration of =
Initial concentration of =
Equilibrium concentration of =
The given balanced equilibrium reaction is,
Initial conc. 0.341 M 0.220 M 0 M
At eqm. conc. (0.341-x) M (0.220-x) M (2x) M
Given : (0.341-x) M = 0.258 M
x= 0.083 M
Thus equilibrium concentartion of = (0.220-0.083) M = 0.137 M
Thus moles of at equilibrium =
At equilibrium , there are 0.274 moles of