Answer:
here are some synonyms of invective are abuse, billingsgate, obloquy, and vituperation.
Answer:
Mass of helium = 4426.9524 g
Mass of hydrogen gas = 2213.4762 g
Explanation:
Pressure = 135 atm
Temperature = 24 °C
Volume = 200 L
Number of moles = ?
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (24 + 273.15) K = 297.15 K
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
135 atm × 200 L = n × 0.0821 L.atm/K.mol × 297.15 K
⇒n = 1106.7381 moles
<u>For helium gas:</u>
Molar mass = 4 g/mol
The formula for the calculation of moles is shown below:
Thus,

<u>For hydrogen gas:</u>
Molar mass = 2 g/mol
The formula for the calculation of moles is shown below:
Thus,

Answer:
Temperature and pressure are the two factors which are responsible for change in state of matter.
Solid – In a solid, the attractive forces keep the particles together tightly enough so that the particles do not move past each other. ... In the solid the particles vibrate in place. Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.
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The reaction of hydrogen gas (H2) with oxygen gas (O2) is a COMBINATION or SYNTHESIS reaction, because multiple substances combine to form fewer substances. Here, the two gases form one substance, water (H2O):
2H2 + O2 -- > 2H2O
1) Molar mass C5H12= 5*12 +1 *12=60+12=72 g/mol
2) 40g C5H12 * 1 mol C5H12/72 g C5H12 = 40/72 mol C5H12
3) C5H12 + 8O2 ------> 5CO2 + 6H2O
by reaction 1 mol 8 mol
from problem 40/72 mol x mol
x=(40/72) * 8/1=(40*8)/72=(40)/9 mol O2
4) M(O2)=2*16 g/mol =32 g/mol
5) (40)/9 mol O2 *(32 g O2/ 1 mol )=(40 * 32)/9 =142.2 g O2