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Sati [7]
2 years ago
8

A sample of aluminium has a mass of 54 gram. What is the mass of the same number of magnesium atom.​

Chemistry
1 answer:
Arada [10]2 years ago
5 0

Answer:

48g of Magnesium.

Explanation:

We know that:

Mole=given mass/molar mass

Then, moles of aluminum = 54/27 = 2.

A/c to question ,

For 2 moles of magnesium it's mass is 2×24=48g.

Hence, the required mass for same number of magnesium atoms is 48g.

(Hope this helps can I pls have brainlist (crown)☺️)

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Mandarinka [93]

Answer:

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7 0
3 years ago
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What is solubility?
erik [133]

2) Solubility is how much solvent will dissolve in solute.

4 0
3 years ago
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Why is the pressure 101.3kPa significant
nydimaria [60]

Answer:

Explanation:

The kPa-kilopascal is the unit of pressure. It was named after Blaise Pascal, a mathematician and physicist.

The kPa is 1000Pa. Kilo stands for 1000. Now what is a pascal?

A pascal is the amount of force(Newton) exerted per unit area.

            1Pa = 1Nm⁻²

At the standard atmospheric level, the pressure is 101.325 x 10³ Nm⁻² i.e the atmosphere exerts a pressure of 101.325 x 10³N in an area of a body.

This unit is used to calculate pressure. It can be converted to other units.

3 0
3 years ago
Nitroglycerin is a dangerous powerful explosive that violently decomposes when it is shaken or dropped. The Swedish chemist Alfr
ELEN [110]

Answer:

4 C3H5N3O9 ------> 6N2 + O2 + 10H2O + 12CO2

Explanation:

Nitroglycerin has a chemical formula C3H5N3O9. The balanced chemical equation is as follows:

4 C3H5N3O9 ------> 6N2 + O2 + 10H2O + 12CO2

We suppose that in a reaction, 44g of carbon dioxide is produced. The mass of nitroglycerin that must have reacted will be calculated as under:

Molecular mass of Nitroglycerin = 227g/mol

Molecular mass of Carbon dioxide = 44g/mol

No. of moles of carbon dioxide produced = 44/44 = 1 mole produced.

Now, from balanced chemical equation, we can see that

12 moles of carbon dioxide are produced by = 4 moles of nitroglycerin.

1 mole of carbon dioxide is produced by = 4/12 = 1/3 moles of nitroglycerin.

Mass of nitroglycerin which produced 1 mole of carbon dioxide =  1/3 x 227 = 75.666 grams.

6 0
3 years ago
How much CaCO3 would have to be decomposed to produce 247 g of CaO
vovangra [49]

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

\tt \dfrac{1}{1}\times 4.41=4.41

mass CaCO₃(MW=100 g/mol) :

\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g

6 0
3 years ago
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