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Sati [7]
2 years ago
8

A sample of aluminium has a mass of 54 gram. What is the mass of the same number of magnesium atom.​

Chemistry
1 answer:
Arada [10]2 years ago
5 0

Answer:

48g of Magnesium.

Explanation:

We know that:

Mole=given mass/molar mass

Then, moles of aluminum = 54/27 = 2.

A/c to question ,

For 2 moles of magnesium it's mass is 2×24=48g.

Hence, the required mass for same number of magnesium atoms is 48g.

(Hope this helps can I pls have brainlist (crown)☺️)

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Answer:

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3 years ago
A scientist measures the standard enthalpy change for the following reaction to be -17.2 kJ : Ca(OH)2(aq) 2 HCl(aq)CaCl2(s)
elixir [45]

Answer: \Delta H^{0}=-173.72 kJ/mol

Explanation: <u>Enthalpy</u> <u>Change</u> is the amount of energy in a reaction - absorption or release - at a constant pressure. So, <u>Standard</u> <u>Enthalpy</u> <u>of</u> <u>Formation</u> is how much energy is necessary to form a substance.

The standard enthalpy of formation of HCl is calculated as:

\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}

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Standard Enthalpy of formation for the other compounds are:

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Water: \Delta H^{0}= -285.83 kJ/mol

Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.

Calculating:

-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H]

-17.2=-1367.46+1002.82-2\Delta H

2\Delta H=17.2-364.64

\Delta H=-173.72

So, the standard enthalpy of formation of HCl is -173.72 kJ/mol

8 0
3 years ago
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Answer:

pretty sure its D

like 85% sure

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