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8090 [49]
3 years ago
5

A 6.87-L sample of gas has a pressure of 0.732 atm and a temperature of 95 °C. The sample is allowed to expand to a volume of 9.

22 L and is cooled to 44 °C. Calculate the new pressure of the gas, assuming that no gas escaped during the experiment.
Chemistry
1 answer:
Jlenok [28]3 years ago
7 0

Answer: The new pressure of the gas, assuming that no gas escaped during the experiment is 0.470 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.732 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 6.87 L

V_2 = final volume of gas = 9.22 L

T_1 = initial temperature of gas = 95^oC=273+95=368K

T_2 = final temperature of gas = 44^oC=273+44=317K

Now put all the given values in the above equation, we get:

\frac{0.732\times 6.87}{368}=\frac{P_2\times 9.22}{317}

P_2=0.470atm

Thus the new pressure of the gas, assuming that no gas escaped during the experiment is 0.470 atm

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See explanation

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4 0
2 years ago
The temperature of a sample of water changes from 10°C to 20°C when the water absorbs 100 calories of heat. What is the mass of
Vlad1618 [11]

Answer:

10 g

Explanation:

Right from the start, just by inspecting the values given, you can say that the answer will be  

10 g

.

Now, here's what that is the case.

As you know, a substance's specific heat tells you how much heat is needed to increase the temperature of  

1 g

of that substance by  

1

∘

C

.

Water has a specific heat of approximately  

4.18

J

g

∘

C

. This tells you that in order to increase the temperature of  

1 g

of water by  

1

∘

C

, you need to provide  

4.18 J

of heat.

Now, how much heat would be required to increase the temperature of  

1 g

of water by  

10

∘

C

?

Well, you'd need  

4.18 J

to increase it by  

1

∘

C

, another  

4.18 J

to increase it by another  

1

∘

C

, and so on. This means that you'd need

4.18 J

×

10

=

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

.

Now look at the value given to you. If you need  

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

, what mass of water would require  

10

times as much heat to increase its temperature by  

10

∘

C

?

1 g

×

10

=

10 g

And that's your answer.

Mathematically, you can calculate this by using the equation

q

=

m

⋅

c

⋅

Δ

T

 

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

Plug in your values to get

418

J

=

m

⋅

4.18

J

g

∘

C

⋅

(

20

−

10

)

∘

C

m

=

418

4.18

⋅

10

=

10 g

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