Answer:
The preservation of biodiversity provides a vital link to critically expand the molecular diversity necessary for successful drug discovery efforts in the future. ... This ongoing loss of biodiversity is altering ecosystem functions and the ability to provide goods and services for human health and well-being
Explanation:
Answer:
B (Metaphase I)
Explanation:
Meiosis is one of the two types of cell divisions that results in 4 daughter cells (gametes) with each having half the number of chromosomes as the parent cell. During meiosis, cell division occurs twice because before the separation of two halves of a duplicated chromosome called sister chromatids, there still need to be separation of homologous pairs, which is a similar but non-identical pair of chromosome received from both parents. Hence, meiosis occurs in a two step division process; meiosis I and meiosis II.
During Prophase I, which is the first stage of meiosis I, homologous chromosomes pair up side by side to form a structure called TETRAD or BIVALENT and likely undergo crossing over( when segments of homologous chromosomes get broken and refixed interchangeably).
After crossing over, the spindle fibres (from the centrosomes) begin to attach to the centromeres of each chromosomes and move them towards the center of the cell called METAPHASE PLATE. Hence, they become aligned on the equator towards either side of the pole. Each chromosome attaches to microtubules from one pole of the spindle and the two homologues of a pair bind to microtubules from opposite poles. Hence, in Metaphase I, homologous pairs, not individual chromosomes, line up at the Metaphase plate/equator for separation.
The orientation of the line up of homologous chromosomes determines which chromosomes enter into the same cell i.e. the alignment of chromosomes towards the same pole determines which chromosomes enter into the same cell to form the genetic composition of gametes. In an organism with two sets of chromosomes (diploid), there are four possible combinations in which chromosomes are arranged in the metaphase plate, resulting in differences in chromosomal distribution in daughter cells/gametes, the process of independent assortment
The correct answer is 97761 * 2, L6050, Z44.8, Z89.11.
In the CPT index when one looks for Prosthetics/Training, then one is directed towards 97761. The code is repeated for every 15 minutes. As 30 minutes are spent in training, so 2 units are reported. In the HCPCS level II codebook when one looks for Disarticulation/Wrist prosthesis, one is directed towards codes L6050, L6055. On the basis of description, the prosthesis is reported with code L6050.
In the alphabetic index of ICD-10-CM, when one looks for fitting/device NOS/prosthetic (external), then one is directed towards the code Z44.8. In the index when one looks for the absence of organ or part (complete or partial)/wrist and hand (acquired) then one is referred towards the code Z89.11.
Answer: The average speed of the toy car during the two trials is 2m/s.
Explanation:
Speed can be defined as a type of scalar quantity in physics through which the rate at which an object travels through a distance is measured in a given amount of time. The formula for determining the speed of a car is:
Speed= distance/ time which has an SI unit of m/s.
From the speed tests carried out on a toy car, the speed of trial 1 is:
Distance= 10 meters
Time= 5 seconds
Therefore trial one speed is 10/5= 2m/s
While the speed of trial 2 is:
Distance= 40meters
Time= 20 seconds
Therefore trial 2 speed is 40/ 20= 2mls
Average speed of the toy car during the two trials is: Sum of both both speeds divided by total number of trials.
Therefore: 2 m/s + 2m/s / 2= 2m/s
From the calculation, the average speed of the toy car during the two trials is 2m/s.
Physical weathering because it affects the appearance by breaking down the rock instead of changing its chemical interior
