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ollegr [7]
3 years ago
10

A mixture of 30 pounds of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates w

orth 90¢ a pound. How many pounds of the $1.50 chocolate were used to make the mixture? If x represents the pounds of $1.50 chocolates used, then which of the following represents the pounds of 90¢ chocolates used?
Mathematics
2 answers:
siniylev [52]3 years ago
8 0

Answer:

10 pounds of the $1.50 chocolates  

20 pounds of the $0.90 chocolates

Hope this helps.

Wittaler [7]3 years ago
8 0

Answer:

20 pounds.

Step-by-step explanation:

Let x pounds of $ 1.50 chocolates is mixed with some pounds of 90¢ chocolates,

Since, the quantity of resultant mixture = 30 pounds,

So, the quantity of  90¢ chocolates = 30 - x

Now, 90¢  = $ 0.90    ( 1 cent = $ 0.100 ),

Thus, the total cost of the resultant mixture

= 1.50x + 0.90(30-x)    ( total cost = number of units × price per unit )

According to the question,

Resultant mixture is sold for $1.10 a pound,

So, the cost of resultant mixture = 1.10(30)

\implies 1.50x + 0.90(30-x) = 1.10(30)

\implies 1.50x + 27 -0.9x = 33

\implies 0.6x + 27 = 33

\implies 0.6x =6

\implies x = 10

Hence, the number of pounds of 90¢ chocolates used = 30 - 10 = 20 pounds.

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