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podryga [215]
4 years ago
6

A photon is scattered from an initially stationary electron within a metal. How does the frequency of the photon change upon sca

ttering?
Physics
1 answer:
sammy [17]4 years ago
5 0

Answer:

The frequency of the photon decreases upon scattering

Explanation:

Here we note that when a photon is scattered by a charged particle, it is referred to as Compton scattering.

Compton scattering results in a reduction of the energy of the photon and hence an increase in the wavelength (from λ to λ') of the photon known as Compton effect.

Therefore, since the wavelength increases, we have from

λf = λ'f' = c

f = c/λ

Where:

f and f' = The frequency of the motion of the photon before and after the scattering

c = Speed of light (constant)

We have that the frequency, f, is inversely proportional to the wavelength, λ as follows;

f = c/λ

As λ = increases, and c is constant, f decreases, therefore, the frequency of the photon decreases upon scattering.

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A sock stuck to the inside of the clothes dryer spins around the drum once every 2.0 s at a distance of 0.50 m from the center o
Rashid [163]

a) 1.57 m/s

The sock spins once every 2.0 seconds, so its period is

T = 2.0 s

Therefore, the angular velocity of the sock is

\omega=\frac{2\pi}{T}=\frac{2\pi}{2.0}=3.14 rad/s

The linear speed of the sock is given by

v=\omega r

where

\omega is the angular velocity

r = 0.50 m is the radius of the circular path of the sock

Substituting, we find:

v=(3.14)(0.50)=1.57 m/s

B) Faster

In this case, the drum is twice as wide, so the new radius of the circular path of the sock is twice the previous one:

r' = 2r = 1.00 m

At the same time, the drum spins at the same frequency as before, therefore the angular frequency as not changed:

\omega' = \omega = 3.14 rad/s

Therefore, the new linear speed would be:

v'=\omega' r' = \omega (2r)

And substituting,

v'=(3.14)(1.00)=3.14 rad/s = 2v

So, we see that the linear speed has doubled.

8 0
3 years ago
A crane lifts a 1,750 kg mass using a steel cable whose mass per unit length is 0.88 kg/m. What is the speed of transverse waves
Sauron [17]

Answer:

139.6m/s

Explanation:

Calculate the tension first, T=m*g

mass(m): 1750kg, gravity(g): 9.8m/s^2

T= 1750*9.8

 =17150N

Then calculate the wave speed using the equation v = √ (T/μ)

v= √(17150N)/(0.88kg/m)

 =139.6m/s

4 0
3 years ago
Why does moon appear to have alot of phases
Bingel [31]
It depends on the angle of the earth, and our point of view. A full moon would occur if we were to be right in front of it.
4 0
3 years ago
Question #4
olga2289 [7]

Answer:

Distance 5 km, Displacement 3 km east

Explanation:

6 0
4 years ago
A student writes the following script for a scene in a futuristic movie: A rocket ship is landing on the Moon where many astrona
Sav [38]

Answer: No crash landing on the surface of the moon and there is no vibration due to low acceleration due to gravity.

Explanation:

The rocket ship can't land on the surface of the moon because it depends on winged flight for its controlled descent to the surface of the Earth.  Since the moon has no real atmosphere, the wings would not be able to glide the craft smoothly to the moon's surface.

The acceleration due to gravity in the moon is very low compared to the earth. The astronauts cannot experience vibration ripple through the Moon’s surface beneath their feet because the low level acceleration due to gravity will drastically affect the weight of the ship.

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3 years ago
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