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Rainbow [258]
3 years ago
8

Please help, no links please! I dont understand stand this question and im going to cry

Physics
2 answers:
marta [7]3 years ago
5 0
The air Inside the balloon is in the gas phase
Vaselesa [24]3 years ago
3 0

Answer:

I'm pretty sure its helium

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A student on the ground observes the sun just as it sets. His friend, who is located 100 meters higher up in a tall building, te
FrozenT [24]

Answer:

Rt≅6377Km

Explanation:

Take a look at the image. The horizontal line is the horizon, and the angle α corresponds to the earth rotation during the 77 seconds.

With this information, we can know the value of α:

α = \alpha= \frac{77s}{1day}*\frac{1day}{24H}*\frac{1H}{60min}*\frac{1min}{60s}*2*\pi  =0.0056rad

Since we have formed a rectangle triangle:

cos\alpha =\frac{Rt}{Rt+100m}   Solving for Rt:

Rt≅6377467m=6377Km

4 0
3 years ago
Radiation is energy that is (5 points) not transferred at all transferred by direct contact of two objects transferred by moving
BARSIC [14]
There isn't a question here so, true
3 0
3 years ago
The frequency of a wave is 1) A) measured in cycles per second. B) measured in hertz (Hz). C) the number of peaks passing by any
7nadin3 [17]

Answer: E) all of the above

Explanation:

Frequency is the number of  vibrations in one second. It is also defined as the number of crests that pass a point in a given time.

The frequency and the wavelength has an inverse relationship.

Frequency is measured in cycles per second or Hertz(Hz).

The relationship between wavelength and frequency of the wave follows the equation:

\nu=\frac{c}{\lambda}

where,

\nu = frequency of the wave

c = speed of light  

\lambda = wavelength of the wave

Thus all the given statements are true.

6 0
3 years ago
Plz answer #2 plz this is 8th grade science / physics
MrRissso [65]
All you need is your science book
5 0
3 years ago
According to Archimedes’ principle, the mass of a floating object equals the mass of the fluid displaced by the object. Use this
Andrew [12]

Answer:

Part a)

\rho = 0.55 g/cm^3

Part b)

\rho_L = 1.49 g/cm^3

Part c)

Since we know that the base area will remain same always

so here the length and width of the object is not necessary to obtain the above data in such type of questions

Explanation:

Part a)

As we know that when cylinder float in the water then weight of the cylinder is counter balanced by the buoyancy force

So here we know

buoyancy force is given as

F_b = \rho_w V_{sub} g

F_b = (1 g/cm^3) (30 - 13.5) Ag

F_b = 16.5 Ag

Now we know that the weight of the cylinder is given as

W = \rho (30 cm)A g

now we have

\rho (30 cm) A g = 16.5 A g

\rho = 0.55 g/cm^3

Part b)

When the same cylinder is floating in other liquid then we will have

F_b = \rho_L (30 - 18.9 )A g

so we have

\rho_L (11.1) Ag = 0.55(30) Ag

\rho_L = 1.49 g/cm^3

Part c)

Since we know that the base area will remain same always

so here the length and width of the object is not necessary to obtain the above data in such type of questions

3 0
2 years ago
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