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My name is Ann [436]
3 years ago
5

What is 4 over 8+ 2 over 8+ 2 over 4?

Mathematics
2 answers:
natita [175]3 years ago
6 0
= 4/8 + 2/8 + 2/4
= 2/4 + 1/4 + 2/4
= 5/4
Lostsunrise [7]3 years ago
3 0
You need LCD or the least common denominator. For 4 over 8 and 2 over 8 have the same denominators except for 2 over 4. You need to ask yourself what times 4 equals to 8? 4 times 2 equals to 8, so multiply 4x2 for the denominator and for the numerator multiply 2x2. Whatever you do to the denominator you have to do the same thing to the numerator. You multiplied 4x2 for the denominator and 2x2 for the numerator and now your fraction is 4 over 8. Now add 4 over 8+ 4 over 8 which is 8 over 8 or 1. Now add 1+ 2 over 8 which is 1 2/8. If you simplify 1 2/8 it will become 1 1/4.

Hope that helped:D
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What binomial do you have to add to the polynomial 2x^2+3y^2-5xy+1 to get the following?
Contact [7]

Binomial -3y^{2}+5xy when added to polynomial 2x^{2} +3y^{2} -5xy+1  gives  polynomial  that does not contain the variable y .

<h3>What is binomial?</h3>

A mathematical expression consisting of two terms connected by a plus sign or minus sign .

Example: x + 2 is a binomial, where x and 2 are two separate terms.

<h3>What is polynomial?</h3>

A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer

According to the question

polynomial 2x^{2} +3y^{2} -5xy+1

when added with  -3y^{2}+5xy  

= 2x^{2}+1   (as 3y^{2} -5xy got cancelled )

that does not contain the variable y

Hence, Binomial -3y^{2}+5xy when added to polynomial 2x^{2} +3y^{2} -5xy+1  gives that does not contain the variable y .

To know more about Binomial and polynomial here :

brainly.com/question/1698358

# SPJ2

3 0
1 year ago
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15.5 rounded to the nearest tenth
Degger [83]
<span>The tenths place is to the right of the decimal point.</span>
In order to round u number to the nearest tenth, you should <span>to the right of the tenths place. Depending on this number you should determine if you will round up or stay the same (if it is bigger than 5 you will round up, if not it will stay the same).
In our case, the number is 15.5 so it is already rounded to the nearest tenth.

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WILL GIVE BRAINLIEST
ludmilkaskok [199]

Answer:

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Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio
JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

Initial =1\ million

6\ years\ later = 500,000

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

\frac{dA}{dt} = kA

Where k represents the constant of proportionality

\frac{dA}{dt} = kA

Multiply both sides by dt/A

\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}

\frac{dA}{A}  = k\ dt

Integrate both sides

\int\ {\frac{dA}{A}  = \int\ {k\ dt}

ln\ A = kt + lnC

Make A, the subject

A = Ce^{kt}

t = 0\ when\ A =1\ million i.e. At initial

So, we have:

A = Ce^{kt}

1000000 = Ce^{k*0}

1000000 = Ce^{0}

1000000 = C*1

1000000 = C

C =1000000

Substitute C =1000000 in A = Ce^{kt}

A = 1000000e^{kt}

To solve for k;

6\ years\ later = 500,000

i.e.

t = 6\ A = 500000

So:

500000= 1000000e^{k*6}

Divide both sides by 1000000

0.5= e^{k*6}

Take natural logarithm (ln) of both sides

ln(0.5) = ln(e^{k*6})

ln(0.5) = k*6

Solve for k

k = \frac{ln(0.5)}{6}

k = \frac{-0.693}{6}

k = -0.1155

Recall that:

\frac{dA}{dt} = kA

Where

\frac{dA}{dt} = Rate

So, when

A = 600000

The rate is:

\frac{dA}{dt} = -0.1155 * 600000

\frac{dA}{dt} = -69300

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

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If a recipe uses 1 1/2 cups of flour and makes 6 servings how many cupes of flour is in one serving
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6/ 1.5 = 4

4 cups of flour in one serving
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