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3 years ago

What is 4 over 8+ 2 over 8+ 2 over 4?

Mathematics

2 answers:

natita [175]3 years ago

6 0

= 4/8 + 2/8 + 2/4
= 2/4 + 1/4 + 2/4
= 5/4

Lostsunrise [7]3 years ago

3 0

You need LCD or the least common denominator. For 4 over 8 and 2 over 8 have the same denominators except for 2 over 4. You need to ask yourself what times 4 equals to 8? 4 times 2 equals to 8, so multiply 4x2 for the denominator and for the numerator multiply 2x2. Whatever you do to the denominator you have to do the same thing to the numerator. You multiplied 4x2 for the denominator and 2x2 for the numerator and now your fraction is 4 over 8. Now add 4 over 8+ 4 over 8 which is 8 over 8 or 1. Now add 1+ 2 over 8 which is 1 2/8. If you simplify 1 2/8 it will become 1 1/4.

Hope that helped:D

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3 years ago

Can someone please help me with this problem

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2 years ago

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I need help with this, neither of my parents can help me and i want to understand.

olga2289 [7]

Answer:

See explanation

Step-by-step explanation:

1. To rewrite the expression

$(4^{\frac{2}{5}})^{\frac{1}{4}},$

use exponents property

$(a^m)^n=a^{m\cdot n}$

So,

$(4^{\frac{2}{5}})^{\frac{1}{4}}=4^{\frac{2}{5}\cdot \frac{1}{4}}=4^{\frac{2}{20}}=4^{\frac{1}{10}}$

2. Why $10^{\frac{1}{3}}=\sqrt[3]{10}?$

Raise both sides to 10 power:

$(10^{\frac{1}{3}})^3=10^{\frac{1}{3}\cdot 3}=10^1=10\\ \\(\sqrt[3]{10})^3=10$

So,

$(10^{\frac{1}{3}})^3=(\sqrt[3]{10} )^3$

3. Simplify $\dfrac{3^4}{9}$

Use the Quotient of Powers Property:

$\dfrac{a^m}{a^n}=a^{m-n}$

Then

$\dfrac{3^4}{9}=\dfrac{3^4}{3^2}=3^{4-2}=3^2$

4. Solve $4\sqrt{2}+5\sqrt{4}$

First, note that $\sqrt{4}=2,$ then

$4\sqrt{2}+5\sqrt{4}=4\sqrt{2}+5\cdot 2=4\sqrt{2}+10$

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2 years ago

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3 years ago

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san4es73 [151]

Answer:

x = 125 ft and y = 250/3 ft

Step-by-step explanation:

Let assume that,

x be the length of the northern part of the fence (parallel to the north wall)

y be the length of the western and eastern pieces of the fence

As well as farmer has $4000 to spend hence we can write,

8x + 8y + 4y = 4000

8x + 12y = 4000

Hence we can say that,

from the above equation we can write

$y=\frac{4000}{12} -\frac{2x}{3}$

We know that area

A=xy.

$A(x) =\frac{500x}{3}-\frac{2x^2}{3}$

we can write

$A'(x) = \frac{500}{3} -\frac{4x}{3}$

equating it 0 we get

$A'(x) = \frac{500}{3} -\frac{4x}{3}=0$

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Also,

$A"(x) = -\frac{4}{3}$

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we can see that A''(x) is always less than 0 hence using second derivative test we can say that x = 125 is a maximum point.

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Hence we can say that dimensions for the plot that would enclose the most area is,

x = 125 ft and y = 250/3 ft

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3 years ago