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liberstina [14]
4 years ago
12

Which number is a common multiple of 7and 4 What is the least common multiple of 18and28

Mathematics
1 answer:
lianna [129]4 years ago
8 0
The least common multiple of 18 and 28 is 252
the common multiple of 7 and 4 is 28
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Rachel solved 50 problems of her Homework correctly and scored 62.5%. How many problems were there in the Homework?
maria [59]

Answer:

80

Step-by-step explanation:

50 problems/x total = 62.5%

50/62.5=0.8 problem for each percent

0.8 * 100 percent = 80 problems

3 0
3 years ago
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The 8th term of an arithmetic sequence is 12.5 and the 13th term is 20. What is the 25th term?
miv72 [106K]
From the 8th to the 13th there are five numbers, and the difference between the 8th and the 13th is 20-12.5=7.5, so the difference between two neighboring number is 7.5÷5=1.5
from the 13th and the 25th there are 12 numbers, so the total difference is 12*1.5=18
so the 25th term is 20+18=38
7 0
3 years ago
How can you tell that this transformation is a dilation?
cluponka [151]
Do you have a picture of the graph, but if there is a dilation there will be a small plane and a big on on the same graph and one will have a ‘ by the point letter representing it’s the 2 image
7 0
2 years ago
Mr lim had just enough money to buy 6 similar lamps. However, he bought 3 such lamps and had $950 left. How much money did mr li
Artyom0805 [142]

Let the cost of a lamp = x

6 lamps would cost 6x

He bought 3 lamps at 3x plus Thad 950 left.

3 lamps plus the 950

Would be the same amount as 6 lamps:

Set up an equation and solve for x:

3x + 950 = 6x

Subtract 3x from both sides:

950 = 3x

Divide both sides by 3:

X = 316.67

Each lamp was $316.67

Multiply the price of a lamp by 6:

316.67 x 6 = 1900

He had $1900

6 0
3 years ago
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How to integrate with steps:<br><br> (4x2-6)/(x+5)(x-2)(3x-1)
joja [24]

\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx

You have a rational expression whose numerator's degree is smaller than the denominator's. This tells you you should consider a partial fraction decomposition. We want to rewrite the integrand in the form

\dfrac{4x^2-6}{(x+5)(x-2)(3x-1)}=\dfrac a{x+5}+\dfrac b{x-2}+\dfrac c{3x-1}

\implies4x^2-6=a(x-2)(3x-1)+b(x+5)(3x-1)+c(x+5)(x-2)

You can use the "cover-up" method here to easily solve for a,b,c. It involves fixing a value of x to make 2 of the 3 terms on the right side disappear and leaving a simple algebraic equation to solve for the remaining one.

  • If x=-5, then 94=112a\implies a=\dfrac{47}{56}
  • If x=2, then 10=35b\implies b=\dfrac27
  • If x=\dfrac13, then -\dfrac{50}9=-\dfrac{80}9c\implies c=\dfrac58

So the integral we want to compute is the same as

\displaystyle\frac{47}{56}\int\frac{\mathrm dx}{x+5}+\frac{10}{35}\int\frac{\mathrm dx}{x-2}+\frac58\int\frac{\mathrm dx}{3x-1}

and each integral here is trivial. We end up with

\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx=\frac{47}{56}\ln|x+5|+\frac27\ln|x-2|+\frac5{24}\ln|3x-1|+C

which can be condensed as

\ln\left|(x+5)^{47/56}(x-2)^{2/7}(3x-1)^{5/24}\right|+C

7 0
3 years ago
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