How many electrons does phosphorous (P) need to gain to have a stable outer electron level? 1 2 3 4
1 answer:
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Answer:
<em>speed of the alpha particle is 2 x 10^7 m/s.</em>
Explanation:
energy of alpha particle = 8.3 Mev
1 Mev = 1.602 x 10^-13 J
8.3 Mev =
solving, = 8.3 x 1.602 x 10^-13 = 1.329 x 10^-12 J
mass of a alpha particle = 6.645 x 10^−27 kg
The energy of the alpha particle is the kinetic energy KE of the alpha particle
KE =
where m is the mass of the alpha particle
v is the velocity of the alpha particle
substituting values, we have
1.329 x 10^-12 =
= 4 x 10^14
= <em>2 x 10^7 m/s</em>