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Paraphin [41]
3 years ago
8

How many electrons does phosphorous (P) need to gain to have a stable outer electron level? 1 2 3 4

Physics
1 answer:
Radda [10]3 years ago
5 0

Answer:

It needs 3 more electrons

Explanation:

For it to be stable it needs to have 8 electrons on the outer shell.

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The electric current amount will vary according to the resistance value when connected to a voltage of a power supply. If resistance is reduced, current will increase. So, if the resistance is infinite (open circuit), the current could be considered zero, or infinitesimal small, if the resistance is zero (of infinitesimal small), the current will tend to be the maximum the power supply can provide. Here is the case of the power supply capability, input resistance, capacity to hold and regulate the output voltage to a certain maximum current, etc. Normally when you short circuit (zero ohms resi

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Which of these statements best describes the role of creativity in science? A. It helps scientists prove non-observable theories
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Hello there.

Which of these statements best describes the role of creativity in science?

It helps scientists create theories which are universal.
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4 years ago
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Is a charge of 5.8×10^-18 is possible
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A physicist comes across an open container which is filled with two liquids. Since the two liquids have different density, there
Dominik [7]

Answer:

496.57492 kg/m³

Explanation:

P_a = Atmospheric pressure = 101300 Pa

\rho_w = Density of water = 1000 kg/m^3

h_w = Height of water = 21.8 cm

h_f = Height of fluid = 30 cm

g = Acceleration due to gravity = 9.81 m/s²

\rho_f = Density of the unknown fluid

Absolute pressure at the bottom

P_{abs}=P_a+\rho_wgh_w+\rho_fgh_f\\\Rightarrow \rho_f=\frac{P_{abs}-P_a-\rho_wgh_w}{gh_f}\\\Rightarrow \rho_f=\frac{104900-101300-1000\times 9.81\times 0.218}{9.81\times 0.3}\\\Rightarrow \rho_f=496.57492\ kg/m^3

The density of the unknown fluid is 496.57492 kg/m³

6 0
3 years ago
Energy of a SpacecraftVery far from earth(at R=\infty), a spacecraft has run out of fuel and its kineticenergy is zero. If only
Firdavs [7]

Answer:

s_e=\sqrt{\frac{2GM_e}{R_e^2}}

Explanation:

In this case mechanical energy is conserved, which means that the sum of the initial kinetic energy and initial potential gravitational energy will be equal to the sum of the final kinetic energy and final potential gravitational energy:

K_i+U_i=K_f+U_f

Which in our case will be:

\frac{mv_i^2}{2}+\frac{-GM_em}{r_i^2}=\frac{mv_f^2}{2}+\frac{-GM_em}{r_f^2}

Which, since v_i=0m/s, r_i=infinity, r_f=R_e, v_f=s_e and canceling <em>m</em> means that:

\frac{s_f^2}{2}=\frac{GM_e}{R_e^2}

Solving for the final velocity we get:

s_e=\sqrt{\frac{2GM_e}{R_e^2}}

6 0
3 years ago
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