Help!! I need to answer this question.

HELP PLEASE ITS DUE IN 10 MIN Use algebraic strategies to solve for x.

mr Goodwill [35]

Answer:

x = 4, x ≠ -1

Step-by-step explanation:

√3x + 4 = x

(√3x + 4)² = x² (Square both sides to get rid of the radical.)

3x + 4 = x²

0 = x² - 3x - 4 (Set everything to 0 by moving everything to one side.)

0 = (x - 4)(x + 1) (Factor.)

x = 4 x = -1

Now we need to check for extraneous solutions:

√3(4) + 4 = 4

√12 + 4 = 4

√16 = 4

4 = 4

√3(-1) + 4 = -1

√-3 +4 = -1

√1 = -1

1 ≠ -1

-1 is an extraneous solution.

8 0

3 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Leni [432]

Answer: $\dfrac{2x^2-1}{x(x^2-1)}$

Step-by-step explanation:

The given function : $y=\ln(x(x^2 - 1)^{\frac{1}{2}})$

$\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}$ [ $\because \ln(ab)=\ln a +\ln b$ ]

$\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}$ [ $\because \ln(a)^n=n\ln a$ ]

Now , Differentiate both sides with respect to x , we will get

$\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1)$ (By Chain rule)

[Note : $\dfrac{d}{dx}(\ln x)=\dfrac{1}{x}$ ]

$\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)$

[ $\because \dfrac{d}{dx}(x^n)=nx^{n-1}$ ]

$=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}$

Hence, the derivative of the given function is $\dfrac{2x^2-1}{x(x^2-1)}$ .

8 0

3 years ago

PLEASE HELP THIS IS A FINAL AND IM SO CONFUSED!!!!

Akimi4 [234]

Answer:

C

Step-by-step explanation:

yeah-ya............... right?

5 0

2 years ago

Say that the economy is in an expansion, causing wages to increase by six percent. if you previously received a monthly salary o

Westkost [7]

From previously received a monthly salary of $1,375.00, Your new monthly salary increase by six percent would be $1,457.50.

What is the percentage?

A percentage is a minimum number or ratio that is measured by a fraction of 100.

You previously received a monthly salary of $1,375.00

Now by economic expansion, causing wages to increase by 6%

Increment of the salary = 6% of 1,375.00

= 6/100 × 1,375

= 0.06 × 1,375

= $82.50

So, your new monthly salary would be = $1,375.00 + $82.50

= $1,457.50

Hence, your new monthly salary would be $1,457.50.

Learn more about percentages;

brainly.com/question/13450942

8 0

2 years ago

In April, the water level in a mountain reservoir increased 0.6 m as the snow began to melt. In May, the water level increased a

Svetach [21]

Step-by-step explanation:

x+0.6+0.3-0.2=14.2

x+0.7=14.2

x=14.2-0.7

x=13.5

8 0

2 years ago