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hammer [34]
3 years ago
13

A conical paper cup has dimensions as shown in the diagram. How much water can the cup hold when full?

Mathematics
2 answers:
sammy [17]3 years ago
7 0

94.2 cm divided by pi which is 3.14 equals to 30 evenly hoped this helped yall out

dusya [7]3 years ago
4 0
<span> By definition, the volume of a cone is given by:
</span> V = (1/3)*( \pi)*(r^2)*(h)&#10;
<span> Where,
 r: radius of the circular base of the cone.
 h: cone height
 The cone radius is given by:
</span> r = d / 2 &#10;
<span> Where,
 d: diameter of the circular base.
 Substituting values we have:
</span> r = 6/2 &#10;&#10;r = 3 cm<span>
 Then, the volume will be:
</span> V = (1/3) * (3.14) * (3 ^ 2) * (10) &#10;&#10;V = 94.2 cm ^ 3<span>
 Answer:
 The volume of the cone is given by:
</span> V = 94.2 cm ^ 3<span>
</span>
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If a bottle contains 16.9 fluid ounces and a person drank 80% of it how many fluid ounces did that person drink?
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The unit rate for 5.99 for 13 Ib
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A water tank already contained 24 gallons of water before a pump was switched to fill it. The pump started at 10:00 am and by 10
grigory [225]

Answer:

The equation to represent  the amount of water that the tank contains (W) after the pump was working for T hours can be given as:

W=32T+24

Step-by-step explanation:

Given:

Water tank initially contained = 24 gallons of water

The pump to fill the tank was switched to fill it.

From 10:00 AM to 10:30 AM the tank contained 40 gallons of water.

By 1:00 PM the tank contained 120 gallons of water.

To write an equation  which will tell the amount of water that the tank contains (W) after the pump was working for T hours

Solution:

Initially, gallons of water in tank = 24

From 10:00 AM to 10:30 AM the tank had 40 gallons of water.

Thus, in half an hour the pump filled = 40-24 = 16 gallons

Using unitary method:

If in \frac{1}{2} of an hour water filled = 16 gallons

So, in 1 hour the water filled will be = 16\times 2 = 32 gallons

In 3 hours the water filled will be = 32\times 3 = 96 gallons

Thus, by 1:00 PM the water in the tank will be = 96+24 = 120 gallons

This confirms the data given for 1:00 PM.

This shows that the rate at  which the pump fills the tank is 32 gallons of water per hour.

The equation to represent  the amount of water that the tank contains (W) after the pump was working for T hours can be given as:

W=32T+24

4 0
3 years ago
(HELP! I HAVE NO TIME) At 2pm, a store had sold 15 packs of toilet paper. By 5pm, the store had sold 57 packs of toilet paper. W
Novay_Z [31]

\mathrm {Hey, there!}

Let's solve your problem:

The answer would be 280%.

We know the following information:

2pm - 15 toilet paper rolls

5pm - 57 toilet paper rolls

We have to find the <u>percent rate of change.</u>

Here is how we will do this problem:

<h3><u>First, Set up a ratio:</u></h3>

Change in the quantity [15 - 57]

-------------------------------------

Original quantity [15]

57 - 15 = 42

<h3><u>Next, we will divide. the ratio.</u></h3>

Given quantity - 42

Number of packs sold at 2pm - 15

Fraction - 42/15

<h3><u>Convert the fraction to a decimal.</u></h3>

Fraction - 42/15

Decimal - 2.8

<h3><u>Make the decimal to a percent.</u></h3>

Decimal - 2.8

Percent - 28%

<u>Add a zero to the 28.</u>

<h2><u>Our answer is 280%</u></h2>

<h3></h3>

4 0
3 years ago
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