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just olya [345]
3 years ago
5

A one-celled organism measures 32 mm in length in a photograph. If the photo has been enlarged by a factor of 100, what is the a

ctual length of the organism?
Mathematics
2 answers:
larisa86 [58]3 years ago
5 0

32 mm = length × 100

(32 mm)/100 = length . . . . . divide both sides by 100

0.32 mm = length

The actual length of the organism is 0.32 mm.

Colt1911 [192]3 years ago
3 0

Let L be the actual length.  Then 100 L = 32 mm, and so L = 3 1/8 mm or 3.125 mm.

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A textbook store sold a combined total of 392 physics and psychology textbooks in a week. The number of physics textbooks sold w
katen-ka-za [31]

Answer:

Psychology textbooks = 98 and physics textbooks = 294

Step-by-step explanation:

Let there are x psychology textbooks sold.

No of physics textbooks sold = 3x

ATQ,

A textbook store sold a combined total of 392 physics and psychology textbooks in a week.

x + 3x = 392

4x = 392

x = 98

It means there are 98 psychology textbooks sold and 3x = 3(98) = 294 physics textbooks sold.

5 0
3 years ago
Which of the h values are solutions to the following equation? h^2=.36
Maru [420]

Answer:

h=0.6, -0.6

Step-by-step explanation:

take the root of both sides and solve

3 0
3 years ago
Which pair of triangles can be proved congruent by the SAS postulate?
Olenka [21]
C. â–łADE and â–łEBA

Let's look at the available options and see what will fit SAS.

A. â–łABX and â–łEDX
* It's true that the above 2 triangles are congruent. But let's see if we can somehow make SAS fit. We know that AB and DE are congruent, but demonstrating that either angles ABX and EDX being congruent, or angles BAX and DEX being congruent is rather difficult with the information given. So let's hold off on this option and see if something easier to demonstrate occurs later.

B. â–łACD and â–łADE
* These 2 triangles are not congruent, so let's not even bother.

C. â–łADE and â–łEBA
* These 2 triangles are congruent and we already know that AB and DE are congruent. Also AE is congruent to EA, so let's look at the angles between the 2 pairs of congruent sides which would be DEA and BAE. Those two angles are also congruent since we know that the triangle ACE is an Isosceles triangle since sides CA and CE are congruent. So for triangles â–łADE and â–łEBA, we have AE self congruent to AE, Angles DAE and BEA congruent to each other, and finally, sides AB and DE congruent to each other. And that's exactly what we need to claim that triangles ADE and EBA to be congruent via the SAS postulate.
5 0
3 years ago
Hey morning help please thanks
WITCHER [35]

Answer:

metaphor

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start
Kamila [148]

Option B: \frac{1}{(m-4)(m-3)} is the correct answer.

Explanation:

The given expression is \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}

Simplifying the expression, we have,

\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}

Factor the equations, m^{2}-16\right and m^{2}-9,we get,

m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)

m^{2}-9=m^{2}-3^2=(m+3)(m-3)

Substituting these factored expressions in the above expression, we have,

\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}

Cancelling the common terms m+3 and m+4 , we get,

\frac{1}{(m-4)(m-3)}

Thus, the expression equivalent to \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )} is \frac{1}{(m-4)(m-3)}

Hence, Option B is the correct answer.

3 0
3 years ago
Read 2 more answers
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