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ANEK [815]
2 years ago
13

In the mathematical expression 4 * 3 + 15 / 3 - 6, which operation is performed first?

Mathematics
1 answer:
sveta [45]2 years ago
5 0
Multiplication would be first 
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Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

3 0
3 years ago
How many centimeters are in 15 meters
pav-90 [236]

15 x 100= 1500 centimeters

4 0
2 years ago
Read 2 more answers
What is the product of one half and two thirds?
attashe74 [19]

Answer:

1/4

Step-by-step explanation:

1/2 × 2/3

= 1×3 = 1

2×2 = 4

Therefore,

1/2 × 2/3 = 1/4//

4 0
2 years ago
2/3 of 39<br><br> 3/4 of 24cm
wolverine [178]

Answer:

The answers would be

78/3

18

Step-by-step explanation:

To find them, simply treat the word "of" as if it means multiply.

2/3 * 39 = 78/3

3/4 * 24 = 18

5 0
3 years ago
4h+7=4h-3 i think i have it but im not sure 100% so i need hlp
SSSSS [86.1K]

                                                 <u>4h + 7 = 4h - 3</u>

Subtract  4h  from each side:            7 = -3

There is no value of  ' h ' that can make this a true statement,
so the equation has no solution.


5 0
3 years ago
Read 2 more answers
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