Answer:
Step-by-step explanation:
Given that,
y' = 17y ( 1-y^7)
Let y=1
Then, y' = 0 for all t
Then show that it is the only stable equilibrium point so that as y→1, t→∞ with any initial value.
So, the graph solution will be
y(0) = 1 and this will be an horizontal line
If, y(0) > 1 then, y' < 0 by inspecting the first equation, so the graph is has decreasing solution.
Likewise, if y(0) < 1 then, y' > 0 and the graph is increasing.
So no matter the initial condition, graph of the solution will be asymptotic to the horizontal line above.
This make the limit be 1.
This shows that x = 1 is a stable equilibrium.
Answer:
Yes they are congruent by SAS (wrong answer)
Edit: the correct answer is by HL
The answer is 2.756 in pound's
Answer:
Step-by-step explanation:
4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.
b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.
c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.
d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.
e). If a parallelogram has four congruent sides, then it must be a SQUARE.
5). Given quadrilateral SELF is a rhombus.
a). All sides of a rhombus are equal,
Therefore, ES = EL = 25
b). Diagonals of a rhombus bisects the opposite angles,
Therefore, m∠ELS = m∠FLS
3x - 2 = 2x + 7
3x - 2x = 7 + 2
x = 9
c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.
m∠ELF = 2(m∠ELS) = 2(2y - 9)
m∠LES = 2(m∠LEF) = 2(3y + 9)
And 2(2y - 9) + 2(3y + 9) = 180
(2y - 9) + (3y + 9) = 90
5y = 90
y = 18
a constant of proportionality is a number you have to multiply x by to get y.
y=kx is the equation that expresses the proportionality of x and y
the constant of proportionality is k, so k=-5
