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strojnjashka [21]
3 years ago
15

a line connecting (5, 6) to another point has an undefined slope. What is the closest point on this line with whole number coord

inates below (5, 6)?
Mathematics
1 answer:
Keith_Richards [23]3 years ago
8 0
Lets do it like this:
As this is a line connecting to another point that has an undefined slope, X is 5 for all values of Y: 
Then 
<span>P1(5,6) </span>
<span>P2(5,7). </span>
<span>P3(5,8).
</span>
I hope this can help you
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Place an value under the radical symbol to make the statement true​
yanalaym [24]

Answer:

The cube root of 48 equals the cube root of 6 times 2.

Step-by-step explanation:

3 0
3 years ago
Find the slope of the line through each pair of points ( -5, 10) , (-16, 8)
dedylja [7]

Answer:

-2/-11 or 2/11

Step-by-step explanation:

8-10=-2

-16--5=-11

-2/-11

6 0
3 years ago
Math
lozanna [386]

Answer:

1. x=6

2. C <-26

3. p<6

4. -5x-44

Step-by-step explanation:

1. 2x = 3(x-2) - 3(x-6)

Distribute

2x= 3x-6 -3x+18

Combine like terms

2x =12

Divide by 2

2x/2 =12/2

x=6


2. C+6<-20

   Subtract 6 from each side

C+6-6 < -20-6

C <-26


3. -5p > -30  

Divide by -5.  Remember to flip the inequality when dividing by a negative

-5p/-5 < -30/-5

p<6


4. -4 - 5(X+8)

Distribute

-4 -5x-40

Combine like terms

-5x-44

6 0
4 years ago
When labeling the sides of our triangle in regards to angle S, side x would be __________.
vampirchik [111]
C. Opposite
This is because the side acrosss the right angle is the hypotenuse
The side across the important angle is the opposite
And the side left is the adjacent
7 0
4 years ago
The polynomial equation x^4 + x^3 + x^2 + x + 1 = 0 has zero positive real roots. Please select the best answer from the choices
const2013 [10]

There are zero positive real roots for the given polynomial equation x^4 + x^3 + x^2 + x + 1 = 0. This is explained by Descarte's rule of signs. So, the best choice is T (true).

<h3>What is Descarte's rule of signs?</h3>
  • Descarte's rule of signs tells about the number of positive real roots and negative real roots.
  • The number of changes in signs of the coefficients of the terms of the given polynomial f(x) gives the positive real zeros of the polynomial.
  • The number of changes in signs of the coefficients of the terms of the given polynomial when f(-x) gives the negative real zeros of the polynomial.

<h3>Calculation:</h3>

The given polynomial equation is x^4 + x^3 + x^2 + x + 1 = 0

On applying Descarte's rule of signs,

f(x)=x^4 + x^3 + x^2 + x + 1

Since there are no changes in the signs of the coefficients of any of the terms in the above polynomial, the polynomial has no positive real roots.

f(-x)=(-x)^4+(-x)^3+(-x)^2+(-x)+1\\      = x^4-x^3+x^2-x+1

Since there are four changes in the signs of the coefficients of the terms of the given polynomial when f(-x), the polynomial has 4 negative real roots.

Therefore, the given polynomial equation has zero positive real roots. So, the correct choice is T(true).

Learn more about Descarte's rule of signs here:

brainly.com/question/11590228

#SPJ1

5 0
2 years ago
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