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3 years ago

David learned 15 definitions in 90 minutes. How much time will he take to learn 10 definitions?

2 answers:

7 0

Hey Anthony!

15........>90 minutes
10.........x minutes

Cross multiply
15x = 90*10
15x = 900
x = 900/15
x = 60

So, David will take 60 minutes to learn 10 definitions.

Best of luck!

Monica [59]3 years ago

3 0

Divide 90 by 15 to find out how many minutes it takes him to learn one definition.

90/15

=6

It takes David 6 minutes to learn one definition.

Next multiply 6 by 10 to find out how long it'll take him to learn 10 definitions

6x10

=60

It'll take David 60 minutes to learn 10 definitions.

I hope this helps!

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Please help ill mark brainliest

anyanavicka [17]

The value of the missing length is 20

Let the missing length be x

From Parallel lines and transversal theorem, we have that

If three or more parallel lines intersect two transversals, then they cut off the transversals proportionally.

Then, we can write that

$\frac{x}{15} =\frac{16}{12}$

∴ $x = \frac{15\times 16}{12}$

x = 20

Hence, the value of the missing length is 20

Learn more here: brainly.com/question/24258397

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3 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at 3 formulas:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

Applying formula (1):

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

Applying formula (2):

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

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allochka39001 [22]

Answer:

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Step-by-step explanation:

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Answer:

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