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Serggg [28]
4 years ago
5

Correct answers only!

Mathematics
1 answer:
saveliy_v [14]4 years ago
5 0

Answer:

1180.12

Step-by-step explanation:

p= 4000

r = 9% =0.09

t =3

plug in into  B = p(1 + r)^t

B = 4000(1 + 0.09)^3

B = 4000(1.09)^3

B =5180.116 round to the 2 decimals

B = 5180.12

make the difference between B, the balance (final amount) and  p, the principal (starting amount) = 5180.12-4000 =1180.12

Read more on Brainly.com - brainly.com/question/16685853#readmore

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Step-by-step explanation:

There is a pattern where every two days the previous log is multiplied by three. If you divide 3 by 2 you get 1.5 this is the increase per one day so just multiply day 6 by 1.5 to get the answer for day 7.

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Solve the system of equations and choose the correct answer from the list of options. x − y = 7 y = 3x + 12
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Step-by-step explanation:

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3 years ago
1/(x-1)x+1/x(x+1)+...+1/(x+9)(x+10)=11/12
nata0808 [166]

Notice that

\dfrac1{(x-1)x} = \dfrac1{x-1} - \dfrac1x \\\\ \dfrac1{x(x+1)} = \dfrac1x - \dfrac1{x+1} \\\\ \vdots \\\\ \dfrac1{(x+9)(x+10)} = \dfrac1{x+9} - \dfrac1{x+10}

That is, the <em>n</em>-th term (where <em>n</em> = -1, 0, 1, …, 9) in the sum on the left side has a partial fraction decomposition of

\dfrac{1}{(x+n)(x+n+1)} = \dfrac1{x+n} - \dfrac1{x+n+1}

and in the sum, some adjacent terms will cancel and leave you with

\dfrac1{(x-1)x} + \dfrac1{x(x+1)} + \cdots + \dfrac1{(x+9)(x+10)} = \dfrac1{x-1} - \dfrac1{x+10} = \dfrac{11}{12}

Now solve for <em>x</em>, bearing in mind that we cannot have <em>x</em> = 0, -1, -2, …, -10 :

\dfrac1{x-1} - \dfrac1{x+10} = \dfrac{11}{12}

Combine the fractions on the left side:

\dfrac{(x+10)-(x-1)}{(x-1)(x+10)} = \dfrac{11}{(x-1)(x+10)} = \dfrac{11}{12}

Then we must have

(x-1)(x+10) = x^2 + 9x - 10 = 12 \implies x^2+9x-22 = (x+11)(x-2) = 0

so that either <em>x</em> = 2 or <em>x</em> = -11.

4 0
3 years ago
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earnstyle [38]

Answer:

A

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A function composition is where one function is substituted within another function and is written g(f(x)). Here we will substitute f(x) into g(x). For g(f(-7)), we substitute -7 for x.

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Now substitute -7 for x.

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6 0
4 years ago
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