Find the midpoint of ab. a) (3,1) b) (1,1) c) (10,4) d) (4,4)
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Answer:
f(x) = -19/9(x + 3)² + 5
Step-by-step explanation:
Given the vertex, (-3, 5) and the point, (0, 14):
Use the following quadratic equation formula in vertex form:
f(x) = a(x - h)² + k
where:
(h, k) = vertex
a = determines whether the graph opens up or down, and makes the graph wide or narrow.
<em>h</em><em> </em>= determines how far left or right the parent function is translated.
<em>k</em> = determines how far up or down the parent function is translated.
Plug in the values of the vertex, (-3, 5) and the given point, (0, 14) to solve for <em>a</em>:
f(x) = a(x - h)² + k
14 = a(0 + 3)² + 5
14 = a(3)² + 5
14 = a(9) + 5
Subtract 5 from both sides:
-14 - 5 = 9a
-19 = 9a
Divide both sides by 9 to solve for a:
-19/9 = 9a/9
-19/9 = a
Therefore, the quadratic function in vertex form is:
f(x) = -19/9(x + 3)² + 5
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