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snow_lady [41]
3 years ago
14

A fitness club requires a one -time free of $100 and dies of $20 every month .write an expression for the total cost of membersh

ip for n months
Mathematics
2 answers:
nydimaria [60]3 years ago
4 0
The expression would be 20n + 100.
ozzi3 years ago
4 0

i think the expression is y= 100+ 20n

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Tax is paid on meals in a restaurant.
liberstina [14]

Answer:

17.52%

Step-by-step explanation:

65.35/11.45 = 0.1752

.1752 * 100

= 17.52

4 0
3 years ago
I need the answers for these please
Luda [366]
11.p=-8, 17-8=9
12.y=11, 3*11=33+16=46
13.t=4, 4*4=16-14=2
14.x=9, -9x 9*8=82-9=72-9=62
15.z=4, 12*4=48-18=30
16.g=0, 4*0=0, 7+0=7
17.x=4, 9*4=36-24=-3
18.q=3, 18*3=48+2=50
19.c=2, 3*2=6-4.5=4.1
20.y=4, 9+4=13+4.8=17.4

8 0
4 years ago
URGENT!!! SOLVE BY TAKING THE SQUARE ROOTS. 50 POINTS
il63 [147K]

Answer:

Step-by-step explanation:

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3 0
3 years ago
3xz(9xy+z)-2yz(x+y-z)
Alisiya [41]

Answer:  27x²yz + 3xz² - 2xy - 2y²z + 2yz²  

<u>Step-by-step explanation:</u>

Use the distributive property.

   3xz(9xy + z)           - 2yz(x + y - z)

= 3xz(9xy)  +  3xz(z)  -2yz(x)   -2yz(y)   -2yz(-z)

=  27x²yz   +   3xz²    -2xy       -2y²z      +2yz²  

3 0
3 years ago
Find the smallest positive integer n such that the digit sum of n is divisible by 5, and the digit sum of n +1 is also divisible
alisha [4.7K]

Answer:

139,999

Step-by-step explanation:

If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999

6 0
2 years ago
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