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Murljashka [212]
3 years ago
6

The high temperature on Tuesday was 5 degrees warmer than the high temperature on Monday. If the high temperature on Monday was

-12F, what was the high temperature on Tuesday?
Mathematics
2 answers:
Montano1993 [528]3 years ago
6 0
The highest temperature on Monday was -12F

The highest temperature on Tuesday was 5 degrees warmer than Monday's
5 degrees warmer than -12F
    is -12F + 5F = -7F

The high temperature on Tuesday was -7F
ollegr [7]3 years ago
3 0
-7 because -12+5 equals -7
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2 years ago
I need some help on this question please
elena-s [515]

Answer:

15

Step-by-step explanation:

Ok so first you need to know how to calculate the volume of a cylinder

I will put the formula here:  V=πr2h

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3 years ago
PLEASE HELP ILL GIVE BRAINLIEST
dusya [7]

1)

(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}

3)

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}

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2 years ago
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stellarik [79]

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4vir4ik [10]

Answer:

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