Answer:
Step-by-step explanation:
Putting values of x in equation
Y = 4(-3) - 4
= - 12 - 4 = - 16
Y = 4(-2) - 4
= - 8 - 4 = - 12
Y = 4(-1) - 4
= - 4 - 4 = - 8
Y = 4(0) - 4
= 0 - 4 = - 4
Y = 4(1) - 4
= 4 - 4 = 0
Y = 4(2) - 4
= 8 - 4 = 4
Y = 4(3) - 4
= 12 - 4 = 8
7+ 15.50X=100
Subtract 7
15.50X= 93
Divide by 15.50
X=6 people
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
Answer:
53q+10
Step-by-step explanation:
(-3q+3)+7(8q+1)
-3q+3+56q+7
53q+3+7
53q+10
Answer:
40
Step-by-step explanation:
