Answer:
Step-by-step explanation:
3√5*√5+3√5*√2+ 4√2*√5+ 4√2*√2
15 +3√10 + 4√10 + 8
23+7√10
Answer:
Step-by-step explanation:
Equate the two opposite Angles
7x - 31 = 5x + 13 Subtract 5x from both sides
7x - 5x - 31 = 13 Combine
2x - 31 = 13 Add 31 to both sides
2x = 13 + 31 Combine the right
2x = 44 Divide by 2
x = 44/2
x = 22
Given:
Equation of line is .
To find:
The equation of line which is parallel line to and passes through (3,5) in function notation.
Solution:
Slope intercept form of a line is
where, m is slope and b is y-intercept.
On comparing the equation with slope intercept form, we get
So, slope of given line is 3.
Slope of parallel lines are same. Thus, the slope of parallel line is also 3.
Point slope form of a line is
where, m is slope.
The parallel line passes through (3,5) with slope 3. So, the equation of line is
Add 5 on both sides.
Function notation of this equation is
Therefore, the equation equation in function notation is .
Therefore, half of 1/4 is 1/8. 1/4 means 0.25 if you devide it by 2 you will get 0.125 so 1/8 is half of 1/4.
Answer:
x = (c -mp)/g
Step-by-step explanation:
Subtract the term not containing x, then divide by the coefficient of x.
gx +mp = c . . . . . given
gx = c - mp . . . . . subtract mp
x = (c -mp)/g . . . . divide by g
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<em>Comment on the process</em>
This process can be described various ways. A usual description is "get the x term by itself on one side of the equal sign, then divide by the x-coefficient."
I like a more general description of the solution to "solve for" problems: undo what is done to the variable, in reverse order.
Here, the variable x is multiplied by g, then added to mp. To undo those operations (in reverse order), first we undo the addition of mp. We accomplish that by subtracting mp, or by adding the opposite of mp, as you wish.
Having done that, we undo the multiplication by g by dividing by g.
(gx)/g = (c -mp)/g
x = (c -mp)/g
The steps we actually perform here are identical to the steps in "get the x-term by itself, ...". However, the process we have described can be applied to any sort of equation, not just a 2-step linear equation.