3 years ago

PLEASE HELP ME WITH MY GEOMETRY HOMEWORK!!!!

Mathematics

1 answer:

Oduvanchick [21]3 years ago

7 0

I don’t see the question

You might be interested in

NEED HELP ASAP PLEASE HELP

marusya05 [52]

It's C.......................

3 0

3 years ago

Read 2 more answers

What is equivalent to 2x-17

Bad White [126]

Get photo math an app just for math it gives u the answers and how to solve it

8 0

3 years ago

Please help, due tomorrow. will give brainlist

Tatiana [17]

Step-by-step explanation:

By Remainder Theorem, f(5) = 91.

=> (5)³ - 4(5) + k = 91

=> 125 - 20 + k = 91

=> 105 + k = 91

=> k = -14.

8 0

3 years ago

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

charle [14.2K]

ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

$g(x) = \frac{ - 5x - 9}{x - 1}$

$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9x + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }$

Since the denominators are the same, they will cancel out,

$(f \circ \: g)(x)= \frac{ - 14x}{ - 14} = x$

8 0

3 years ago

In <ABC angle A is 41°. Side b is 65cm, side c is 50cm and side a is unknown. Solve for side a.

lara31 [8.8K]

Side a is 50cm long.

8 0

4 years ago