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V125BC [204]
3 years ago
15

Solve 3sinx-4sin^3 x= -1

Mathematics
1 answer:
postnew [5]3 years ago
5 0
Hello,

Since 3sin x-4sin^3x=sin (3x)  (*****)
3sin x-4sin^3x=-1
==>sin (3x)=-1
==>3x=3π/2 +2kπ
==>x=π/2+2kπ/3, k being an integer

(*****)
sin (3x)=sin(x+2x)=sin x cos2x+cos x sin 2x
=sin x(cos²x-sin²x)+2cos²x sin x
=sin x(cos²x+2cos²x-sin²x)
=sinx(3(1-sin²x)-sin²x)
=3sin x-4sin^3x
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Answer:

first option

Step-by-step explanation:

Given

f(x) = \frac{2x^2+5x-12}{x+4} ← factorise the numerator

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3 years ago
Can someone pls help need it ASAP and can you pls explain in full detail how to do it
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Answer:

x= 1 , y=4

Step-by-step explanation:

x-y= -3 => Equation 1

x+5y= 21 => Equation 2

<u>Substitut</u><u>ion</u><u> </u><u>Method</u><u>:</u>

<u>Substitu</u><u>te</u><u> </u><u>Equation</u><u> </u><u>1</u>=>

x=y-3 <= Equation 3

Put x=y-3 in Equation 2:

x+5y=21

( y-3)+5y=21

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Step-by-step explanation:

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