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3 years ago

Find the nth term of this quadratic sequence 3 8 15 24

Mathematics

1 answer:

olga2289 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

A quadratic sequence is a form. of mathematical progression of numbers in which the subsequent differences between each consecutive term differ by the exact amount. This is known as the common second difference.

Hence in this case,

we have

S= 3+8+15+24+…..+Tn - 1.

S=. 3+8+15+……………..Tn-1 + Tn

Deducting 2nd series from the first

We have 0=3+5+7+…….Tn

Hence, we have Tn= n (n+2)

= 24 (9+2)

= 24 + 11

= 35

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A total of 70 tickets were sold for a concert and earn the organizers $804. If the cost of each ticket is either $10 or $12, how

crimeas [40]

Answer:

52 tickets cost $10 and 18 tickets cost $12

Step-by-step explanation:

10x+12y=804. (1)

x+y=70. (2)

From (2)

x=70-y

Substitute x=70-y into (1)

10x+12y=804

10(70-y)+12y=804

700-10y+12y=804

700+2y=804

2y=804-700

2y=104

y=104/2

y=52

Recall

x+y=70

x+52=70

x=70-52

x=18

52 tickets cost $10 and 18 tickets cost $12

5 0

3 years ago

Write 30x3+5x in factored form.

yaroslaw [1]

5x(6^2 +1)
Is 30x3+5x in factored form

3 0

2 years ago

Please answer the question in the picture below

Elanso [62]

The answer is b because there is a negative in the exponent and the number needs to be a single digit and 54 is double digit. hope this helps!

5 0

3 years ago

In a sample of 100 students, 30 wear size medium t-shirts. Use a proportion to calculate approximately how many medium t-shirts

Talja [164]

Answer:

282 students

Step-by-step explanation:

7 0

3 years ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

6 0

3 years ago