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3 years ago

Find the nth term of this quadratic sequence 3 8 15 24

Mathematics

1 answer:

olga2289 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

A quadratic sequence is a form. of mathematical progression of numbers in which the subsequent differences between each consecutive term differ by the exact amount. This is known as the common second difference.

Hence in this case,

we have

S= 3+8+15+24+…..+Tn - 1.

S=. 3+8+15+……………..Tn-1 + Tn

Deducting 2nd series from the first

We have 0=3+5+7+…….Tn

Hence, we have Tn= n (n+2)

= 24 (9+2)

= 24 + 11

= 35

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5+14a=9a - 5 Please help

posledela

Answer:

a=2

Step-by-step explanation:

5+14a=9a-5 subtract 9a from both sides

5+5a=-5 subtract 5 from both sides

5a=-10 divide by 5 on both sides

a=-2

hope you do well :)

8 0

3 years ago

Sierra sawed 10 1/2 inches off the end of a board. the remaining board was 37 1/2 inches long. how long was the boared that sier

ivann1987 [24]

37 1/2 +10 1/2 = 48 inches
48 inches is your answer ;)

6 0

3 years ago

Two angles are supplementary. The measure

BlackZzzverrR [31]

Answer:

57°

Step-by-step explanation:

Let's assume the measurement of the second angle is x.

so, following the problem

(2x + 9) + x = 180

2x + x = 3x

=> 3x + 9 = 180

=> 3x = 180 - 9

3x = 171

x = 171/3

x = 57°

57° is the smallest angle

5 0

2 years ago

Of the cartons produced by a company, 8% have a puncture, 7% have a smashed corner, and 0.7% have both a puncture and a smashed

Viktor [21]

Answer:

The probability that a randomly selected carton has a puncture or a smashed corner is 0.143

Step-by-step explanation:

we know that P(A∪B) = P(A) + P(B) - P(A∩B).

since given that P(A) = Probability of getting puncture = 0.08

P(B) = probability of getting smashed corner = 0.07

P(A∩B) = probability of getting both puncture and smashed corner = 0.007

P(A∪B) = probability of getting any of them

so P(A∪B) = 0.08 + 0.07 -0.007 = O.143

5 0

3 years ago

Eric throws a biased coin 10 times. He gets 3 tails. Sue throw the same coin 50 times. She gets 20 tails. Aadi is going to throw

iren2701 [21]

Answer:

(1) The correct option is (A).

(2) The probability that Aadi will get Tails is $\frac{2}{5}$ .

Step-by-step explanation:

It is provided that:

Eric throws a biased coin 10 times. He gets 3 tails.
Sue throw the same coin 50 times. She gets 20 tails.

The probability of tail in both cases is:

$P(\text{Tail})=\frac{3}{10}$
$P(\text{Tail})=\frac{20}{50}=\frac{2}{5}$

(1)

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

In this case we need to compute the proportion of tails.

Then according to the Central limit theorem, Sue's estimate is best because she throws it n = 50 > 30 times.

Thus, the correct option is (A).

(2)

As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:

$P(\text{Tail})=\frac{20}{50}=\frac{2}{5}$

Thus, the probability that Aadi will get Tails is $\frac{2}{5}$ .

7 0

3 years ago

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