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Diano4ka-milaya [45]
3 years ago
13

Find the nth term of this quadratic sequence 3 8 15 24

Mathematics
1 answer:
olga2289 [7]3 years ago
6 0

Answer:

35

Step-by-step explanation:

A quadratic sequence is a form. of mathematical progression of numbers in which the subsequent differences between each consecutive term differ by the exact amount. This is known as the common second difference.

Hence in this case,

we have

S= 3+8+15+24+…..+Tn - 1.

S=. 3+8+15+……………..Tn-1 + Tn

Deducting 2nd series from the first

We have 0=3+5+7+…….Tn

Hence, we have Tn= n (n+2)

= 24 (9+2)

= 24 + 11

= 35

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Find the indicated values in each shape.
Natalija [7]

Answer:

30

Step-by-step explanation:

the formula is a^2+b^2=c^2

18^2+24^2=c^2

900=c^2

c=30

6 0
2 years ago
If one out of 12 students at a school share a locker how many share a locker in a school of 456
Kobotan [32]

Answer:

456/12= 38  means 38 kids share a locker

Step-by-step explanation:


3 0
2 years ago
Read 2 more answers
How do I find out how many solutions does each system of equations have?
iragen [17]
To do that you should put it in slope intercept form and then graph, you should already know how to do this.
6 0
3 years ago
Read 2 more answers
Which of the following would be an appropriate alternative hypothesis?
Dennis_Churaev [7]

Answer:

a. The population proportion is less than 0.65

True, we ar interested in see if the population proportion is (less, higher, not equal) to a specified value.

Step-by-step explanation:

1) Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

2) Solution to the problem

a. The population proportion is less than 0.65

True, we ar interested in see if the population proportion is (less, higher, not equal) to a specified value.

b. The sample proportion is less than 0.65

FALSE, we are interesed on parameters, not in statistics like the sample proportion when we conduct a hypothesis test.

c. The population proportion is equal to 0.65

FALSE, the alternative hypothesis can never have an equal sign.

d. The sample proportion is equal to 0.65

FALSE, the alternative hypothesis can never have an equal sign. And we are interesed on parameters, not in statistics like the sample proportion when we conduct a hypothesis test.

e. both (a) and (d)

FALSE, a its correct but option d no.

5 0
2 years ago
If A is a 2 × 2 matrix, then A × I = <br> and I × A =
krok68 [10]

Since the multiplication between two matrices is not <em>commutative</em>, then \vec A\, \times\,\vec I \ne \vec I \,\times \,\vec A, regardless of the dimensions of \vec A.

<h3>Is the product of two matrices commutative?</h3>

In linear algebra, we define the product of two matrices as follows:

\vec C = \vec A \,\times \vec B, where \vec A \in \mathbb{R}_{m\times p}, \vec B \in \mathbb{R}_{p\times n} and \vec C \in \mathbb{R}_{m \times n}     (1)

Where each element of the matrix is equal to the following dot product:

c_{ij} = \left[\begin{array}{cccc}a_{i1}&a_{i2}&\ldots&a_{ip}\end{array}\right]\,\bullet\,\left[\begin{array}{ccc}b_{1j}\\b_{2j}\\\vdots\\b_{pj}\end{array}\right], where 1 ≤ i ≤ m and 1 ≤ j ≤ n.     (2)

Because of (2), we can infer that the product of two matrices, no matter what dimensions each matrix may have, is not <em>commutative</em> because of the nature and characteristics of the definition itself, which implies operating on a row of the <em>former</em> matrix and a column of the <em>latter</em> matrix.

Such <em>"arbitrariness"</em> means that <em>resulting</em> value for c_{ij} will be different if the order between \vec A and \vec B is changed and even the dimensions of \vec C may be different. Therefore, the proposition is false.

To learn more on matrices: brainly.com/question/9967572

#SPJ1

3 0
2 years ago
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