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hjlf
3 years ago
6

The university police department must write, on average, five tickets per day to keep department revenues at budgeted levels. Su

ppose the number of tickets written per day follows a Poisson distribution with a mean of 8.9. Find the probability that exactly four tickets are written on a randomly selected day.
Mathematics
1 answer:
katrin [286]3 years ago
6 0

Answer:

3.566%

Step-by-step explanation:

The probability formula for a poisson distribution is:

P( k )=\frac{\lambda^{k}e^{-\lambda}}{k!} \\

λ is the average of events

e is the euler's number

k is the number of events you want to know the probability

For this :

λ = 8.9 (on average the number of tickets is 8.9 per day)

k = 4 (you need to find the probability that exactly 4 tickets are written per day)

P( k=4 )=\frac{8.9^{4}e^{-8.9}}{4!}=0,03566 =3.566\%

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The mean of this data set is 9. What number is missing?<br><br> 11,20,_,3,1
kherson [118]
Let the missing number be x

Mean is the total sum of data over the number of data therefore,

(11+20+x+3+1) / 5 = 9
Then simplify
(35 + x) / 5 = 9
Then multiply 5 to both sides
35 + x = 45
Then subtract 35 to both sides to find x
X= 10

Hope this helps!

7 0
2 years ago
Can you help me plz <br><br> take your time tho
AnnZ [28]

Answer:

d

Step-by-step explanation:

the reasoning for this is because you count all the 2's and the little number in the corner and then you can't leave the 7 so you put the x7 for that reason

7 0
2 years ago
Read 2 more answers
Can someone help me out, please?
GenaCL600 [577]
Rectangle, triangle, and I believe square
3 0
3 years ago
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
Can someone help answer this
kolezko [41]

Answer:

v = 55

Step-by-step explanation:

Plug in the values provided into the equation

v = u + at

v = 23 + 8 * 4

Solve

v = 23 + 8 * 4

v = 23 + 32

<u>v = 55</u>

6 0
2 years ago
Read 2 more answers
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