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hjlf
3 years ago
6

The university police department must write, on average, five tickets per day to keep department revenues at budgeted levels. Su

ppose the number of tickets written per day follows a Poisson distribution with a mean of 8.9. Find the probability that exactly four tickets are written on a randomly selected day.
Mathematics
1 answer:
katrin [286]3 years ago
6 0

Answer:

3.566%

Step-by-step explanation:

The probability formula for a poisson distribution is:

P( k )=\frac{\lambda^{k}e^{-\lambda}}{k!} \\

λ is the average of events

e is the euler's number

k is the number of events you want to know the probability

For this :

λ = 8.9 (on average the number of tickets is 8.9 per day)

k = 4 (you need to find the probability that exactly 4 tickets are written per day)

P( k=4 )=\frac{8.9^{4}e^{-8.9}}{4!}=0,03566 =3.566\%

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Answer:

A= 3,B = 2

Hope it helps you

if yes mark me brainliest

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Check the picture below.  So the parabola looks more or less like so.

let's recall that the vertex is half-way between the focus point and the directrix, at "p" units away from both.

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\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{we'll use this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-2\\ k=5\\ p=-1 \end{cases}\implies 4(-1)(y-5)=[x-(-2)]^2\implies -4(y-5)=(x+2)^2 \\\\\\ y-5=-\cfrac{1}{4}(x+2)^2\implies y=-\cfrac{1}{4}(x+2)^2+5

6 0
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Step-by-step explanation:

1) If we divide 3.75/3=1.25 which is the amount of time she takes per yard so if we add another yard to what she has already done we find she only could do one more yard in 5 hours 3.75+1.25=5.00 So she can only rake 4 yards in 5 hours

2) If we divide 20.25/3=6.75 we find that each ticket is $6.75 so we must divide that by 47.25 to get the amount of tickets 47.25/6.75=7


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