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3 years ago

what can you erase with a eraser and your finger answer this correctly and you get 25 points and brainly

Mathematics

1 answer:

stellarik [79]3 years ago

7 0

Answer:

a dry-erase maker

Step-by-step explanation:

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Please answer Ill give 5 stars to right answers: a neighbors dog barked at tana the last 4 out of 5 times she walked by their ho

oksian1 [2.3K]

Ratio of dog bark is 4:5

Multiply that by 20 each side

Ratio is now 80:100

So 80%

If they walk past 45 time you just have to multiply the ratio 4:5 by 9

36:45

So the dog would bark 36 times

6 0

2 years ago

Pl help it’s for a grade show work if you can

Savatey [412]

Answer:

m degree 2

Step-by-step explanation:

mujhe 1 hii pata hai sorry

8 0

3 years ago

A fraction bar. The top bar is labeled 1. 4 bars underneath the bar are labeled one-fourth. 5 bars underneath the 4 bars are lab

joja [24]

Answer:

Step-by-step explanation:

$3/4$ * $5/2\$ = $15/8 = 1 \frac{7}{8}$

6 0

2 years ago

Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D

viva [34]

Answer:

$\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C$

Step-by-step explanation:

So we have the indefinite integral:

$\int (\ln(x))^2dx$

This is the same thing as:

$=\int 1\cdot (\ln(x))^2dx$

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

$u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}$

Simplify:

$du=\frac{2\ln(x)}{x}dx$

And:

$dv=(1)dx\\v=x$

Therefore:

$\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx$

The x cancel:

$=x\ln(x)^2-\int2\ln(x)dx$

Move the 2 to the front:

$=x\ln(x)^2-2\int\ln(x)dx$

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

$=x\ln(x)^2-2\int 1\cdot\ln(x)dx$

Let u be ln(x) and let dv be (1)dx. Thus:

$u=\ln(x)\\du=\frac{1}{x}dx$

And:

$dv=(1)dx\\v=x$

So:

$=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)$

Simplify the integral:

$=x\ln(x)^2-2(x\ln(x)-\int (1)dx)$

Evaluate:

$=x\ln(x)^2-2(x\ln(x)-x)$

Now, we just have to simplify :)

Distribute the -2:

$=x\ln(x)^2-2x\ln(x)+2x$

And if preferred, we can factor out a x:

$=x(\ln(x)^2-2\ln(x)+2)$

And, of course, don't forget about the constant of integration!

$=x(\ln(x)^2-2\ln(x)+2)+C$

And we are done :)

8 0

3 years ago

If x=0 and y<0, where is the plot (x,y) located

docker41 [41]

Mark me the Brainliest!

Answer:

The point will be plotted on Y axis

5 0

2 years ago